gas → Gas Law Q1) When 3.0 mol oxygen is heated at a constant pressure of 3.25 atm, its temperature increases from 260 K to 285 K.47 Given the molar heat capacity of oxygen at constant pressure is 29.4 JK-¹mol-¹.@raise Imol →IK → #294 amount of gas + Pressure → fixed Calculate 9, ΔΗ, w and ΔΕ (in kJ). mol (1) Find q = MCAT 9²= 3m61 x 29.4JK ² mol ¹x (285-260) K = 2205] =2.2051J (3) Find w = -PAV La Find AH = G :. At constant P, H = 9p -2.205 kJ = PV=nRT RA R-V Charles Law When Temperature was change Volume change ↓ K VRT A(PV)= (RT)A PAV = nR ↓ Constant ↓ change expand 8.314 Jmol·¹K²
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![4:48 PM Tue 24 Oct
Q
Chem Notes
no
x
Ch1
249 1 Mole Ex
| lyfind AH = q
:. At constant P,
= -2.205 kJ
Ch3
H=99
249 1 Mole Ex.. x
T
gas → Gas Law
Q1) When 3.0 mol oxygen is heated at a constant pressure of
(1) Find q = mCAT
9²= 3 m61 x 29,4 JK ² mol ¹x (285-260) K
= 2205] =2.2051J (3) Find w = -PAV
Constant
**
3.25 atm, its temperature increases from 260 K to 285 K.
Given the molar heat capacity of oxygen at constant
pressure is 29.4 JK-mol-¹.raise Imol → IK →→ #294
amount of gas + Pressure → fixed
Calculate q, AH, w and AE (in kJ).
mol
249 2 Matters..
A (PV)= (RT)A
PAY = nRT₁
PV=nRT
R=RK Charles Law
XT
الر
2022-23 IGC...
When Temperature was change
Volume change
↓
K VLT
↓
change expand
8.314 Imol· ¹K²
X
31%
te
Ch3
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