Given an input string, delete recursively all the duplicate adjacent characters and return a string where all those adjacent characters that are the same have been reduced to just a single character.
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- Given an input string, complete a helper method that extracts the vowels and returns the string of the vowels in the input string recursively. All strings are lowercase. Do not use any loops or regular expressions. Test case 1: extractVowel("i love you 3000") "ioeou" Test case 2: extractVowel("aiueo") "aiueo" Given methods: public static String extractVowel (String str) { return extractVowelHelper (str, 0, ""); } 1 2 3 4 private static boolean isVowel (char c){ return c == 'a' || c == 'e' || c == 'i' || c == '0' || == 'u'; } 5. 6. 7.public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringIn Python, The function add_char_counts takes three parameters: a string s and two strings of length 1, char1 and char2, and returns the total number of times either char1 or char2 appears in s. For example, the word "scallions" has 2 s's and 1 n, so add_char_counts("scallions", "s", "n") returns 3. Hint: Use a string method to help solve this problem (count). You do not need an accumulator. For example: Test Result print(add_char_counts('Indiana', 'a', 'b')) 2 print(add_char_counts('BAHAMAS', 'A', 'B')) 4 print(add_char_counts('Mississippi', 'i', 'M')) 5 print(add_char_counts("spam spam spam spam", "s", "p")) 8
- Given a long string use recursion to traverse the string and replace every vowel (A,E,I,O,U) with an @ sign. You cannot change the method header. public String encodeVowels(String s){ // Your code here }Help me please: A palindrome is a string that reads the same both forward and backward. For example, the string madam is a palindrome. Write a program that uses a recursive function to check whether a string is a palindrome. Prompt the user for a string. If the string is a palindrome output a message in the following format: madam is a palindrome else Hello is not a palindrome Your program must contain a value-returning recursive function that returns true if the string is a palindrome and false otherwise. Do not use any global variables; use the appropriate parameters.Given 2 strings, return their concatenation, except remove the last character of each and swap the order of the inputted words. The strings will be at least length 3. Ex: If the input is: bird penguin the output is: pengiubir Ex: If the input is: loving csce the output is: csclovin
- java: Run length coding is a method to represent a string in a more compact manner. Each character that occurs more than 2 times in a row is represented by the character and a number following it. Two examples are: "abba" → "abba""abcccbbbba" → "abc3b4a"Write a function that calculates how many characters the encoded string is shorter than the original.Use for loop in Java language Write the method stringSplosion().* * The method takes one parameter, a non-empty String str (such as "Code") and* returns a String in the form "CCoCodCode". Notice that this includes the* first character of the original String, followed by the first two characters,* and so on until the whole String is used.* * Examples: stringSplosion("Code") returns "CCoCodCode" stringSplosion("abc")* returns "aababc" stringSplosion("x") returns "x"* * @param str the input String to process.* @return a new String as described above.Section Test of Application... Note: You need to press "Final Submit" for your pr Given a string in which the same character occurs in many.consecutive character elements. Your task is to find the characters that have even frequency and are consecutive. Display the sum of every frequency count (For even frequency only). Example1: Input aaabbaccccdd Input String Output: Explanation: Input string "aabbaccccdd" contains 'a' 3 times, b' 2 times, again 'a' 1 time, 'c' 4 times, and 'd 2 times Here, the frequency of b.c and d is even and the frequency count is 2,4 and 2 respectively. Hence the output32-4-2%3D8 Example2: input: vdkkmmmnn Output Buns andur-
- Use for loops in Java Language Write the method catDog.* * Given a String str, return true if the words "cat" and "dog" appear the same* number of times in the string.* * Examples: catDog("catdog") returns true catDog("catcat") returns false* catDog("1cat1cadodog") returns true* * @param str the String to examine.* @return true if there are the same number of cats and dogs.Given a string str and number n, write a program that recursively appends a copy of string str n times and returns the resulting string. For example: RecuriveCopy("a", 10) // -> "aaaaaaaaaaa" RecursiveCopy("blah", 5) // -> "blahblahblahblahblahblah" For this exercise, complete the following function. n is the number of copies to add to str: function RecursiveCopy(str, n) { // your code here } Part 2: Call RecursiveCopy Write another function that calls RecursiveCopy() and returns the following string output: "The resulting string [x] has [y] characters". [x] should be replaced by the result from RecursiveCopy) and [y] should be replaced by the number of characters in the resulting string. You may pick the arguments to RecursiveCopy in CountChars or have the user provide input. I will leave this up to you. function CountChars() { } // your code here // call RecursiveCopy(..) // returns a formatted string For example: console.log(CountChars()) // -> "The resulting string blahblahblahblah…Given a string, write a method that returns the number of occurrences of substrings "baba" or "mama" in the input string recursively. They may overlap. Do not use any loops within your code. Do not use any regular expressions and methods such as matches, split, replaceAll. "Maa mana, Test case 1: countBabaMama ("aba babaa amama ma") 2 Test case 2: countBabaMama ("bababamamama") 4