This is for a water and wastewater review. It's not for a grade I just need to understand the problem, please include equations and choose one of the answer choices. Given the following dissolved oxygen data for an aeration test with Cg = 9 mg/L, the KLa value measured during the test ismost nearly?Time (min)Concentration (mg/L)110-0.14 1/min0.17 1/minOc 0.17 1/minOD. 0.14 1/min

Volumetric oxygen mass transfer coefficient=KLaKLa=KL×AVwhere A=inerfacial area of mass transfer…

Given the following dissoived oxygen data for an aeration test with Cg = 9 mg/L, the KLa value measured during the test is most nearly? Time (min) Concentration (mg/L) 10 0.14 1/min 0.17 1/min Oc0.17 1/min OD.0.14 1/min

Given the following dissoived oxygen data for an aeration test with Cg = 9 mg/L, the KLa value measured during the test is most nearly? Time (min) Concentration (mg/L) 10 0.14 1/min 0.17 1/min Oc0.17 1/min OD.0.14 1/min

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: For a wastewater sample, the three-day biochemical oxygen demand at incubation temperature of 20°C…

A: Given data- BOD at 3 days at 20o=200 mg/Lk=0.22 day-1To Find-BOD at 5 days at 20o

Q: A COD test was carried out on a batik factory wastewater. The relevant information is as follows,…

Q: Determine the ultimate BOD of a waste water sample which was subjected to the BOD determination as…

A: This question is related waster water from Environment Engineering or waste water Engineering. In…

Q: Design an aeration tank in a sewage treatment plant with following information and report the…

A: The question is based on the aeration tank. The value of influent flow, BOD, and mixed liquor…

Q: A BOD analysis was performed on a municipal wastewater. The 300 mL test bottle was filled with 2.0%…

A: Given Values: 300 mL test bottle. Dilution factor=2% Initial Dissolved Oxygen (DOi) =8.3 mg/L…

Q: Solids analyses were conducted on the domestic wastewater that was tested for BOD. The tests were…

A: Total solid Total solids in water are made up of dissolved solids as well as suspended and…

Q: CIVIL ENGINEERING (ii) A treatment plant disposes 50 MLD of treated effluent into a river. The river…

A: Given- Discharge Qw=50 MLDRiver discharge QR=20 m3/sRiver DO DOR=8 mg/LEffluent BOD yw=50 mg/LRiver…

Q: For a wastewater sample, the three-day biochemical oxygen demand at incubation temperature of 20°C…

A: Solution: Given- k=0.22mg/l , T1 = 5days, T2=3 days, BOD3 = 200mg/l

Q: 8. The BODS of a waste sample was found to be 160 mg/L. The initial oxygen concentration of the…

Q: The concentration of VSS in the returned flow rate to the aeration tank = 4000 mg/L while the MLVSS…

A: Given data- Aeration Tank-VSS concentration= 4000 mg/LMLVSS concentration= 2500 mg/LMLSS…

Q: The data are given as follows: Weight of evaporating dish: 53.5430 g Weight of evaporating dish and…

Q: Question 8 Given the following dissolved oxygen data for an aeration test with Cs = 9 mg/L, the KLa…

A: When a supersaturated solution is to be degassed or removal of gas takes place,then equation can be…

Q: Determine fixed and volatile solids concentration using the data given in example I and as under:…

Q: A coagulation treatment plant with flow of 0.5 metre cube per second is dosing alum at 23 milligram…

Q: In a BOD test,1.0 ml of raw sewage was diluted to 100 ml and the dissolved oxygen concentration of…

A: Answer:- Biochemical Oxygen demand (B.O.D):- B.O.D is a measure of the oxygen utilized by bacteria…

Q: 3. Table below shows the concentration of dissolve oxygen for a BOD test, diluted by 100. Time…

A: The given data is: Dilution Factor (DF)= 100 Time (days) Diluted sample DO (mg/l) 0 7.95 1…

Q: In a certain situation, wastewater discharged into a river, mixes with the river water…

A: given- waste water DO=2 mg/Ldischarge =1.10 m3/sriver DO==8.3 mg/Ldischarge =8.70 m3/s

Q: 4. The sketch below shows streams in and out of a primary clarifier in a wastewater treatment plant.…

Q: Sanitary Engineering Potential of Hydrogen (pH) same question please help me: 1-What are…

Q: Following table includes the records taken during a ring-infiltrometer experiment. Using these data…

A: time infiltration capacity 7:00 101 7:02 5.5 7:05 10 7:10 10 7:20 13 7:30 8 7:40 4.5…

Q: The application rate of a certain chemical is recommended at 4 kg/ha. The calibration test of a…

A: Insecticide application rate=4kg/ ha = 4 l/ha Sprayer capacity = 16 liters Discharge rate = 1.2…

Q: wastewater into the tank is 10 liters/sec and the influent concentration of suspended solids (SS)…

A: According to given data A settling tank is used to remove suspended solids from wastewater. The…

Q: The results of a jar test on a surface water supply sample revealed that the optimum dose of alum…

A: Data given: Optimum dose of alum (Al2(SO4)3.14H2O) as coagulant = 17 mg/l The water has total…

Q: If the concentration of Na, Ca and Mg in a water sample are 345, 60 and 18 mg/l, respectively, then…

A: This question is related to The Irrigation Engineering. In this question we calculate the SAR of…

Q: A wastewater sample of 100 ml was filtered through the filter paper and the filtered water was…

A: Suspended Solids=Weight of residueVolumeWeight of residue=7.76-0.1=7.66gmsSuspended…

Q: 2. The BOD5 of a waste sample was found to be 60 mg/L The initial oxygen concentration of BOD…

A: V1=10ml DOf=8.6mg/l

Q: Trickling filter is a fixed-bed biological reactor that operates under aerobic conditions. It is…

Q: A BOD analysis was conducted on a partially-treated sewage at 25°C. Only 20% of the volume of BOD…

Q: A laboratory provides the following solids analysis for a wastewater sample: TS = 290 mg/L; TDS = 37…

A: Total solidsTS=290 mg/lTotal dissolved solidsTDS=37 mg/lFixed suspended solidsFSS=38 mg/la…

Q: The following data were obtained in a laboratory study conducted for the determination of the…

A: Step 1

Q: Problem #7: A domestic sewage analysis was carried out for solid analysis. The test was performed…

A: Hi there!! since you have asked multiple questions, we will solve the first question for you. If you…

Q: The data of an activated sludge process are B. as follows: MLSS = 5000 mg/lit %3D Flow = 0.15 m3/sec…

Q: Then, you were asked to find out the biodegradability of this wastewater by conducting a 5-day…

Q: Determine the total dissolved solids concentration using following data: i) Volume of filterable…

Q: A 2% solution of a sewage sample is kept at an incubation temperature of 20°C. If initial DO…

A: BOD = (DOinitial -DOfinal)*(Dilution factor) DOinitial = 8.5mg/l DOfinal = 5.5mg/l Dilution factor…

Q: Q.107 An activated sludge system is operating under equilibrium conditions with following…

Q: Prepare a neat sketch of the dissolved oxygen concentration profile downstream of a wastewater…

A: Oxygen sag curve

Q: A mix of wastewater and river water with a discharge of 10 m3/sec has a BOD5 of 28 mg/L, a DO of 8…

A: As the critical BOD is higher than the given BOD initial =28 mg/l

Q: A BOD analysis was conducted on a partially- treated sewage at 25°C. Only 20% of the volume of BOD…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: Adding 20ml sample to a 300ml DO bottle causes its dissolved oxygen concentration to decrease by 10…

Q: 2. The BOD5 of a waste sample was found to be 60 mg/L The initial oxygen concentration of the BOD…

Q: For a wastewater sample, the three-day biochemical oxygen demand at incubation temperature of 20°C…

Q: B) Chlorine usage in the treatment of 30 MLD of water is 10 kg/day. The residual after 10 minutes…

A: To find out the dosage and chloride demand of water.

Q: Q2/ Calculate the gas flow rate in sef/day for a natural gas is following in porous media at…

A: Given :

Q: Table Q1-2 Weight (g) Mass of residue after drying at 105 ¿C Mass of residue after ignition at 550…

Q: The mixture has a temp. = 20 °C %3D Deoxygenation const.= 0.28 day1 %3D Average flow = 0.3 m/s,…

A: Lo = BODu = 25.8mg/L DOmix = 7.2mg/L T (Temperature) = 20o C KD = 0.28/day Vav = 0.3m/s y(average…

Q: In a BOD test, the amount of organic matter remaining in the wastewater was measured at certain time…

A: Finding out ultimate BOD and BOD rate constant k.

Q: The absolute viscosity of the peanut oil is 41x10-3 Pa-s and the specific gravity is 0.95. If the…

A: The given data is shown below: Absolute viscosity=41×10-3 Pa-sSpecific gravity=0.95Discharge=8.6…

Q: A BOD analysis was performed on a municipal wastewater. The 300-mL test bottle was filled with 2.0%…

Q: Computation: Ratio Strength, PPM, mg% Show your complete solution. 1. If a city water supply has a…

A: Given data, Amount of nitrate ion present = 250 ppm

Concept explainers

Engineering Standards and Codes

Standards are technical publications designed to ensure the reliability of goods, products, methods, or services. They establish technical requirements, specifications, guidelines, features, or design procedures. Standards recommend a set of tolerance for design, processes, operations, production methods, or equipments used in a particular area. Standards are not legally binding unless they are accepted as code or regulation.

Question

This is for a water and wastewater review. It's not for a grade I just need to understand the problem, please include equations and choose one of the answer choices.

Given the following dissolved oxygen data for an aeration test with Cg = 9 mg/L, the KLa value measured during the test is
most nearly?
Time (min)
Concentration (mg/L)
1
10
-0.14 1/min
0.17 1/min
Oc 0.17 1/min
OD. 0.14 1/min

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1 solution

VIEW

Step 2 value of KLa

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

H Gy Q#4:The table shows data of a wastewater sample collected from a river with a temperature of 30 °C analyzed for the BODs test. The rate constant is 0.2 day-¹ at the lab temperature (20 C). Find BODs at the river. Initial dissolved oxygen, mg/L 9 What will be the BOD7 at the river? Final dissolved oxygen, mg/L 3.5 Sample volume, ml 35
A BOD analysis was conducted on a partially- treated sewage at 25°C. Only 20% of the volume of BOD test incubator was filled with the sewage, and the dissolved oxygen values listed below were measured. Time Dissolved oxygen (mg/L) time O 1 2 3 4 5 6 Dissolved oxyen (mg/L) 8.5 7.7 6.5 4.8 3.5 ? ? By considering minimum dissolved oxygen at day 6 is valid for BOD test, determine the following: (i) Reaction rate K25. (ii) 25BOD5 from the drawn graph. (iii) 30BOD3. (iv) COD of the sample.
A raw sewage sample was brought in for total suspended solids and volatile solids analysis. A portion of the sample was poured into a tared evaporating dish and weighed. The sample was then heated at 105°C for 4 hours, weighed, heated at 550°C overnight, and weighed again. The data are as follows: • Tare wt. 42.9073g• Wt of sample 104.4680g• 105 °C wt. 45.4140g• 550 °C wt. 43.3236g What is the TSS in g/L? What percent of the solids are volatile?
Determine fixed and volatile solids concentration using the data given in example I and as under: Weight of evaporating dish plus residue after ignition at 550 degrees * C W_{3} = 30.3630g Volume of filterable sample = 50 mL Weight of evaporating dish with dry solids, W_{2} = 30.3675g
T Settled sludge and filter wash water from water treatment are thickened in Problems 703 clarifier-thickeners prior to mechanical dewatering. The settled sludge volume is 1150 gpd with 1.0% solids, and the backwash is 9800 gpd containing 500 mg/l of suspended solids. Calculate the daily quantity of thickened sludge, assuming a concentration of 3.0% solids
3. A 100 mL of wastewater sample was drying on a 0.5 g empty dish weight at 104 °C to weight 0.5625 g. Another 100 mL of the same wastewater was first filtered and the filtrate was dried on a 0.5 g dish at 104 °C to weight 0.5325 g. Determine in mg/L the:a) TSb) TSSc) TDSd) VSS assuming it represents 70% of TSS
Problem 1. A wastewater sample is examined for its solid contents. The ionic strength (μ) of wastewater is 0.01. It is known that 30% of total dissolved solids (TDS) is organic. The volumetric settleable solid concentration is determined as 20 mL/L using Imhoff Cone. It is assumed that 40% of total suspended solids (TSS) is equal to dry-settleable solids. The volumetric settleable solids composes of 2% of dried solids and 98% of water. The density of volumetric settleable solid concentration is given as 1020 g/L. Use information given in problem, calculate: a) Total Dissolved Solids (TDS) concentration as mg/L. b) Total Suspended Solids (TSS) concentration as mg/L. c) Total Solids (TS) concentration as mg/L.
The results of a jar test on a surface water supply sample revealed that the optimum dose of alum (Al2(SO4)3.14H2O) as coagulant is 17 mg/L. Furthermore, the water has total alkalinity = 50 mg/L as CaCO3; pH = 7.8; and residual turbidity at optimum alum dose = 4 NTU. The water treatment plant has a mean flow of 10m3/hour. Determine: The kg of alum per year needed in the operation of the plant. The residual alkalinity in the sample, following the addition of alum at optimum dose. Solve parts (a) and (b) if instead of alum, ferric chloride (FeCl3) were used as coagulant. Assume the numerical jar test results are the same as those with alum.
Determine the total dissolved solids concentration using following data: i) Volume of filterable sample = 50 mL ii) Tare weight of the evaporating dish, W_{1} = 30.3419 iii) Weight of evaporating dish with dry solids, W_{2} = 30.3675g
A wastewater sample was diluted 10% with tap water for conducting BOD Test. The DO content in wastewater sample was 1.2 mg/l and water was 6 mg/l. After 5 days incubation at 20°C, the DO of the sample was 0.5 mg/l. Calculate (i) 5 day BOD of wastewater and (ii) ultimate BOD. Assume K₂0 = 0.12/day. ion:
No of Blows moisture content(%) 13 45.53 20 44.28 23 43.5 39 41.17 a) Determine the Liquid Limit. b) Determine the Plasticity Index given water content of 21.48 and 26.52 c) Determine the Liquidity Index if the natural water content is 36.84. (Input this on the answer box) Submit your Solution. Box your Final Answer.
Solids analysis is one of the most widely used parameters for assessing water quality. Use the following data to determine (a) total solids (TS); (b) volatile solids (VS); (c) dissolved solids (DS); (d) total suspended solids (TSS), and (e) total volatile suspended solids (TVSS) all in mg/L. A sample volume of 150 ml was used in performing all solids analyses. Tare mass of evaporating dish = 24.3520 g Mass of evaporating dish plus residue after evaporation @ 105°C = 24.3970 g Mass of evaporating dish plus residue after ignition @ 550°C = 24.3850 g Mass of Whatman filter and tare Mass of Whatman filter and tare after drying @ 105°C Residue on Whatman filter and tare after ignition @ 550°C = 1.5103 g 1.5439 g 1.5199 g