GPS (Global Positioning System) satellites orbit at an altitude of 2.3x107 m. Part A Find the orbital period. Express your answer in hours. View Available Hint(s) T = Submit Part B 15| ΑΣΦ Find the orbital speed of such a satellite. Express your answer in meters per second. ► View Available Hint(s) ΤΙ ΑΣΦ V = Submit ? ? h m/s
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- Check Your Understanding Verify that vector v V obtained in Example 2.14 is indeed a unit vector by computing its magnitude. If the convoy in Example 2.8 was moving across a desert flatland—that is, it the third component of its velocity was zero—what is the unit vector of its direction of motion? Which geographic direction does it represent?The angle of elevation 0 of the sun in the sky at any latitude Lis calculated with the formula sane-cos Dcos L cos wsanD sinL wis the number of radians that the Earth has rotated through since noon when w-0. Dis the declination of the sun. Westville has latitude L-30 . Find the angle of elevation 8 in degrees of the sun at 3 PM on February 29, 2012, where at that time D-0.125 and w-0.7854 O 36.8 28 O 05 26.9"A rocket is launched at ? = 0 seconds. Its height, in meters above sea-level, is given by the equationℎ = −4.9?2 + 325? + 227A. Find the time it takes the rocket to reach the maximum height? (Round answer to 2 decimal places.) B. What is the maximum height attained by the rocket? (Round to the nearest whole number)
- The average distance between Earth and the Sun is 1.5 ✕ 1011 m. (a) Calculate the average speed of Earth in its orbit (assumed to be circular) in meters per second (b) What is this speed in miles per hour? Please answer BThe acceleration due to gravity, g, is constant at sea level on the Earth's surface. However, the acceleration decreases as an object moves away from the Earth's surface due to the increase in distance from the center of the Earth. Derive an expression for the acceleration due to gravity at a distance h above the surface of the Earth, g₁. Express the equation in terms of the radius R of the Earth, g, and h. &h= Suppose a 91.75 kg hiker has ascended to a height of 1802 m above sea level in the process of climbing Mt. Washington. By what percent has the hiker's weight changed from its value at sea level as a result of climbing to this elevation? Use g = 9,807 m/s² and R= 6.371 x 106 m. Enter your answer as a positive value. weight change =A miner in the underground tunnel walks 9 m due East, 90 m due South and 119 m due West. What was the total distance covered by the miner? Select one. Oa no answer Ob 218 m Oc 142.126/m Od mcomplete given.
- A guy travels 33.4325 m in the direction of 122.3175 degrees from the positive x-axis, then 21.7794 m in the direction of 228.9742 degrees from the positive x-axis, and lastly 37.2575 m in the direction of 16.1243 degrees from the positive x-axis. How far has he progressed since his beginning? Give precise answers to four decimal places. Only enter the numerical value.I don't understand how to find the height. I had gotten 139 m as my answer but it is not correct.Az = -4.00 km, A, = -8.00 km. Express your answer in kilometers. ? JA = km
- Solve the problem. The angle of elevation 0 of the sun in the sky at any latitude Lis calculated with the formula sine-cos D cos L cos o sanD sin L wis the number of radians that the Earth has rotated through since noon when w-0. Dis the declination of the sun. Westville has latitude L-379. Find the angle of elevation 0 in degrees of the sun at 3 PM on February 29, 2012, where at that time D-01e5 and w0.7854 368 O 28 26.97. A man walks 19.1982 m directed 149.1237 degrees from the positive x-axis, then he walks 45.3282 m directed 309.5635 degrees from the positive x-axis, then finally he walks 26.1062 m directed 317.9913 degrees from the positive x-axis. How far he is now from his starting point? Express your answers accurate to four decimal places. Enter only the numerical valueSupply all missing information with the correct numerical values. Do not include the units. Round off all answers to two decimal places. Do not forget the negative sign (-) if needed. Borsalino wants to buy some ice cream in the nearest convenience store. He has to walk 5.3 meters, 12 degrees in the north of east direction to reach the doorstep of the convenience store. He then enters the store and walks straight to cashier, two meters due northwest. Let be the displacement vector with a magnitude of 5.3 meters directed 12 degrees in the north of east direction, and let be the displacement vector with a magnitude of two meters due northwest. Express vectors and in unit vector component form. = + = + The net displacement is given by the vector sum: . = + By Pythagorean theorem,the magnitude of the displacement is: = meters. The direction of the resultant displacement is: north of east.