Graphical Interpretation of Work: The resultant force on an object over a 0.50-s time interval is plotted in the graph in the figure. How much work did this force do on the object during the 0.50-s interval? F (N) 5.0 0 -5.0 22 J 50 J OJ O 12.5 J O-25 J 5.0 10 x (m)

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter6: Energy Of A System
Section: Chapter Questions
Problem 24P: The force acting on a particle is Fx = (8x 16), where F is in newtons anti x is in meters. (a) Make...
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Graphical Interpretation of Work: The resultant force on an object over a 0.50-s time interval is
plotted in the graph in the figure. How much work did this force do on the object during the 0.50-s
interval?
F (N)
5.0
0
-5.0
22 J
O 50 J
OOJ
O 12.5 J
O -25 J
5.0
10
x (m)
Transcribed Image Text:Graphical Interpretation of Work: The resultant force on an object over a 0.50-s time interval is plotted in the graph in the figure. How much work did this force do on the object during the 0.50-s interval? F (N) 5.0 0 -5.0 22 J O 50 J OOJ O 12.5 J O -25 J 5.0 10 x (m)
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