H H с H2C а) H2C- С—SH KSH SK H2S H2C- H2 NH3 NH2 HC b) HC || HC. + H20 + H30 HC. .CH .CH H H2 C. OK H2 + H20 + КОН H3C H3C d) HC HO. H20 HC + H30 HC. CH HC, CH H
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Identify following reaction is in equilibrium <->, or products favored ->, or reactants favored <-
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- 11) Using the data: C₂H4(8), AH°f=+51.9 kJ mol-1, S = 219.8 J mol-1 K-1 CO₂(g), AH°f = -394 kJ mol-¹, So=213.6 J mol-1 K-1 H₂O(1), AH°f = -286.0 kJ mol-¹, S = 69.96 J mol-¹ K-1 O₂(g), AH°f = 0.00 kJ mol-¹, So = 205 J mol-1 K-1 Calculate the maximum amount of work that can be obtained, at 25.0 °C, from the process: C₂H4(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(l) A) 1492 kJ mol-1 B) 1380 kJ mol-1 C) 1451 kJ mol-1 D) 2422 kJ mol-1 E) 1332 kJ mol-1 252253010 armitoron (simodo estoitumoleriam nosalmatinon (diuon a Jotamerd tion 2AJ(S) + 3 Hzsou(cnो ->PIo. (S०५)2)07 ) + 3Hac3) जाणe जयार Joovchcadl प्रावd + AIनSoq) 3ुका ? when li18 mod of Ad ieactd with 1:14 mod of H2So4.What is qrxn? -3661 J -146.4 J +146.4 J +3661 J
- Br / || a CH₂ NaCN DMF N₁" DMF Хок 1-BuOH H₂O H₂O5. Hence show that: OU (hv exp(-ẞhv)) hv exp(-2ẞhv) =-3Nhv + oß (1-exp(-ßhv)) (1-exp(-ẞhv)) Hint 1: you will need to use the quotient rule: yf'(x) xf'(y) f'(x) f'(y) (f'(y))² (f'(y))² Hint 2: the following identity will avoid you having to use the chain rule: d (1 − e√(x)) = − f'(x)e√(x) dxBb MYJCC Blackboard Learn WebAdvisor for Students JCC Self Service Bb UTF-8 Syllabus_CHM%20151%2 X A ALEKS - Griffin Barden - Learn m/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IJczzdcvSCzsqTCIDqNGV3bKghMfPmUcQ4ENkmiXn9QCwgeDPDkQ06yszYWEsPcekwL0-Qg619rekU7404HgFAGbEZaDr080?1oBw7QYjlbavbSP O THERMOCHEMISTRY Understanding the definitions of heat and work A mixture of gaseous reactants is put into a cylinder, where a chemical reaction turns them into gaseous products. The cylinder has a piston that moves in or out, as necessary, to keep a constant pressure on the mixture of 1 atm. The cylinder is also submerged in a large insulated water bath. (See sketch at right.) 1 atm pressure uoIsid cyli From previous experiments, this chemical reaction is known to release 241. kJ of energy. The position of the piston is monitored, and it is determined from this data that the system does 133. kJ of work on the piston during the reaction. gases exothermic Is the reaction exothermic or endothermic?…
- Please answer Q1. specially (i).LEKS - Brittney Alvarez - Leam /alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-liGmxpvVN4ENzvdYC-70kXyMz36BqJhw3sVP-BxK_53zl8Tf7PSmOkvprMFImNhBhubnrMFFRG2do9Q_LSoq981YO_PCy8o?1oBw7QYjlbavbSPXtx-YCjsh_7mMmrq" gmail * e alvarez family blog + a amazon O onedrive V Blackboard Leam Official Miami Dade. A Rate My Professors.. * Course Hero D HiMovies.to | Watc. Disney+ | Movies a O CHEMICAL REACTIONS Percent yield of chemical reactions Brittm Liquid octane (CH;(CH,) CH;) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide (CO2) and gaseous water CH.) (H,0). If 7.40 g of water is produced from the reaction of 9.14 g of octane and 49.0 g of oxygen gas, calculate the percent yield of water. Round your answer to 3 significant figures. % IIIKS - Jasmine Bassler - Learn cg1/x/istexe/To_u-IgNslkr7j8P3jH-lvUrTNdLZh5A8CnG03PBGuXr8iCPa7ZMmym9hTWHc1BkL64lfbHd6ekurSojptYikmiZnHbvsb8OJQdwhEkLV6oo6Tp3Ecq?1oBw7OYjlbavbSPXtx-YCjsh_/mMmr4*item O CHEMICAL REACTIONS Dilution Jasmine A chemist must dilute 20.3 mL of 1.37 M aqueous calcium bromide (CaBr,) solution until the concentration falls to 1.00 M. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Be sure your answer has the correct number of significant digits. mL II
- "Carboxylic acid Derivatives: Acyl Halides and Anhydrides, Esters, Amides" from your, textbook, and you will analyze presented organic compounds to find and discuss the differences between them and finally recognize what type of carboxylic acid derivative are they?What is the specific rotation 20[a ]D of the following molecule? * a = 4.42° C = 0.1g.mr" | = 10cm - 44.20 O +4.420 +0.4420 +44.20Order the following carbon-carbon bonds in order of increasing vibrational frequency (lowest to highest in cm-1) I C=C 0 0 0 0 | < ||| < || || < ||| < | || < | < ||| ||| < || < | II C-C III C=C