H2(g) + I2(g) ⇄ 2 HI(g)     Kp = 69 at 340 K 50.0 g of HI is injected into an evacuated 5.00-L rigid cylinder at 340 K. What is the total pressure inside the cylinder when the system comes to equilibrium?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter13: Chemical Equilibrium
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 H2(g) + I2(g) ⇄ 2 HI(g)     Kp = 69 at 340 K

50.0 g of HI is injected into an evacuated 5.00-L rigid cylinder at 340 K. What is the total pressure inside the cylinder when the system comes to equilibrium?

Expert Solution
Step 1

The equilibrium reaction taking place is given as,

=> H2 (g) + I2 (g) ⇄ 2 HI (g)                                              Kp = 69 

Given : Mass of HI taken = 50.0 g

And volume of vessel = 5.00 L

Molar mass of HI = Atomic mass of H + atomic mass of I = 1 + 127 = 128 g/mol.

Since mass = moles X molar mass

=> 50.0 = Initial moles of HI X 128

=> Initial moles of HI = 0.390625 mol.

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