H2(g) + I2(g) ⇄ 2 HI(g) Kp = 69 at 340 K 50.0 g of HI is injected into an evacuated 5.00-L rigid cylinder at 340 K. What is the total pressure inside the cylinder when the system comes to equilibrium?
H2(g) + I2(g) ⇄ 2 HI(g) Kp = 69 at 340 K 50.0 g of HI is injected into an evacuated 5.00-L rigid cylinder at 340 K. What is the total pressure inside the cylinder when the system comes to equilibrium?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter13: Chemical Equilibrium
Section: Chapter Questions
Problem 11ALQ: Explain why the development of a vapor pressure above a liquid in a closed container represents an...
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H2(g) + I2(g) ⇄ 2 HI(g) Kp = 69 at 340 K
50.0 g of HI is injected into an evacuated 5.00-L rigid cylinder at 340 K. What is the total pressure inside the cylinder when the system comes to equilibrium?
Expert Solution
Step 1
The equilibrium reaction taking place is given as,
=> H2 (g) + I2 (g) ⇄ 2 HI (g) Kp = 69
Given : Mass of HI taken = 50.0 g
And volume of vessel = 5.00 L
Molar mass of HI = Atomic mass of H + atomic mass of I = 1 + 127 = 128 g/mol.
Since mass = moles X molar mass
=> 50.0 = Initial moles of HI X 128
=> Initial moles of HI = 0.390625 mol.
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