91Z 18th lecture Equili...->+1EF, = 0;Ay -200 cos 30° N - 60 N = 0A, = 233 Nprepared by: Ahmed Raad, MSCEENGINEERING MECHANICS STATICSHomework:1. Draw the free-body diagram of each object.S00 N4m(a)(4)600Nm200 N/m3m-2m2 m(b)(e)400 N/m400 N3m3m2 mIm(c)(r)2. Determine the horizontal and vertical components of reaction at thesupports. Neglect the thickness of the beam.500 Ib600 lb ftA5 ft-5 t-5 ftprepared by: Ahmed Raad, MSCEENGINEERING MECHANICS STATICS3. Determine the components of reaction at the fixed support A. Neglect thethickness of the beam.200 N 200 N 200 N30°-1 m--1m 1m-400 N3 m60

To find 1. Draw the free body diagram of each object.

Answered: Homework: 1. Draw the free-body diagram…

Homework: 1. Draw the free-body diagram of each object. SOIN (al (4) 600 N m -2m 200 Nm 2m- (b) (e) 400 N/m 400 N -3m -3m Im (ce)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

91
Z 18th lecture Equili...
->
+1EF, = 0;
Ay -
200 cos 30° N - 60 N = 0
A, = 233 N
prepared by: Ahmed Raad, MSCE
ENGINEERING MECHANICS STATICS
Homework:
1. Draw the free-body diagram of each object.
S00 N
4m
(a)
(4)
600Nm
200 N/m
3m
-2m
2 m
(b)
(e)
400 N/m
400 N
3m
3m
2 m
Im
(c)
(r)
2. Determine the horizontal and vertical components of reaction at the
supports. Neglect the thickness of the beam.
500 Ib
600 lb ft
A
5 ft
-5 t
-5 ft
prepared by: Ahmed Raad, MSCE
ENGINEERING MECHANICS STATICS
3. Determine the components of reaction at the fixed support A. Neglect the
thickness of the beam.
200 N 200 N 200 N
30°
-1 m--1m 1m-
400 N
3 m
60

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