How do you derive Equation 4 from Equations 1 and 3? Equation 1 is Current, I= emf/(R+r) and Equation 3 is power, P= IV= I^2R . Equation 4 is Making use of Eq. (1) in Eq. (3), one can show that power, P, supplied by the battery to the resistive load, R, can be written as: P=emf^2(R/(R+r)^2

How do you derive Equation 4 from Equations 1 and 3? Equation 1 is Current, I= emf/(R+r) and Equation 3 is power, P= IV= I^2R . Equation 4 is Making use of Eq. (1) in Eq. (3), one can show that power, P, supplied by the battery to the resistive load, R, can be written as: P=emf^2(R/(R+r)^2

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter1: Getting Started

Section: Chapter Questions

Problem 31PQ: Perform the following arithmetic operations, keeping the correct number of significant figures in...

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

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Context: Source of EMF and RC Circuits
How do you derive Equation 4 from Equations 1 and 3? Equation 1 is Current, I= emf/(R+r) and Equation 3 is power, P= IV= I^2R . Equation 4 is Making use of Eq. (1) in Eq. (3), one can show that power, P, supplied by the battery to the resistive load, R, can be written as: P=emf^2(R/(R+r)^2

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