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How many electrons are involved in each of the following reactions?
Part A)
2Al2O3→4Al+3O2
Part B)
2ZnO+CO→3CO2+2Zn
A) 2Al2O3 --> 4Al + 3O2
The oxidation state of Al and O atom in Al2O3 are +3 and -2 respectively.
The oxidation state of Al and O2 are 0 and 0 respectively.
So, 4Al+3 + 12e- ---> 4Al
6O2- ---> 3O2 + 12e-
Hence, in the given reaction 12 electrons are involved.
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