How many moles of Mg*2 in 6.00 mL of a 6.0N Mg3(PO4)2 Solution ? First we have to convert moles into equivalents Mg3(PO4)2 3 Mg*2 + 2 PO43 1 mol = equivalents 1 mol MP = mol Mg*2 eq mol (6.00 x 10-3 L)(- eq MP (- eq mol Mg*2 mol MP)(- -) = mol Mg*2 mol MP а. 250. b. 100.0 с. 2 d. 30.00 е. 6 f. 24 g. 3 h. 36 i. 18.0 j. 1 k. 6.00 x 10-3 I. 3.60 x 10-2 m. 6.00 x 10-2 n. 5 o. 3.0 x 10-2 p. 1.80 x 10-2 q. 7.65 x 10-10 r. 2.63 S. 7.89 t. 5.26 u. 1012 V. 109 w. 106 х. 103 у. 95.21 z. 10

Introductory Chemistry: A Foundation
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How many moles of Mg*2 in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ?
First we have to convert moles into equivalents
Mg3(PO4)2
3 Mg*2
2 PO43
+
1 mol =
equivalents
1 mol MP =
mol Mg*2
eq
mol
(6.00 x 10-3 L)(-
%3D
eq MP
-) =
eq
mol Mg*2
mol MP)(--
) =
mol Mg*2
mol MP
а. 250.
b. 100.0
С. 2
d. 30.00
е. 6
f. 24
g. 3
h. 36
i. 18.0
j. 1
k. 6.00 x 10-3
I. 3.60 x 10-2
m. 6.00 x 10-2
n. 5
О. 3.0 х 102
p. 1.80 x 10-2
q. 7.65 x 10-10
r. 2.63
S. 7.89
t. 5.26
и. 1012
v. 109
w. 106
Х. 103
у. 95.21
z. 10
Transcribed Image Text:How many moles of Mg*2 in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ? First we have to convert moles into equivalents Mg3(PO4)2 3 Mg*2 2 PO43 + 1 mol = equivalents 1 mol MP = mol Mg*2 eq mol (6.00 x 10-3 L)(- %3D eq MP -) = eq mol Mg*2 mol MP)(-- ) = mol Mg*2 mol MP а. 250. b. 100.0 С. 2 d. 30.00 е. 6 f. 24 g. 3 h. 36 i. 18.0 j. 1 k. 6.00 x 10-3 I. 3.60 x 10-2 m. 6.00 x 10-2 n. 5 О. 3.0 х 102 p. 1.80 x 10-2 q. 7.65 x 10-10 r. 2.63 S. 7.89 t. 5.26 и. 1012 v. 109 w. 106 Х. 103 у. 95.21 z. 10
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