how to solve for the density of air? can anyone explain why the answer is =0.00191 slug/ft^3?

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how to solve for the density of air? can anyone explain why the answer is =0.00191 slug/ft^3?

Given
P= 10psi
T= -20°F
We know that,
Density of air at a state is given by,
%3D
RT
P =(10psi) (144 fn/4f¢) =
I=(-20°F+ 460o)°R = 440°R
& R 1716 ft.llof Islug.°R
2
where
140 ebf/ft?
%3D
%3D
There fore,
2
1440 lbf/ft
(1716 ft Bbf/slug.R) (440°R)
3=0.00191 slylft'
Transcribed Image Text:Given P= 10psi T= -20°F We know that, Density of air at a state is given by, %3D RT P =(10psi) (144 fn/4f¢) = I=(-20°F+ 460o)°R = 440°R & R 1716 ft.llof Islug.°R 2 where 140 ebf/ft? %3D %3D There fore, 2 1440 lbf/ft (1716 ft Bbf/slug.R) (440°R) 3=0.00191 slylft'
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