Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H,0,(aq) — 2н,00) + 0,(@) The activation energy for this reaction is 75 kJ-mol. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ-mol-1. At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °C? T = K
Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H,0,(aq) — 2н,00) + 0,(@) The activation energy for this reaction is 75 kJ-mol. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ-mol-1. At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °C? T = K
Chapter8: Reaction Rates And Equilibrium
Section: Chapter Questions
Problem 8.76E
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Question
![Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation
2Н,0, (aq)
2 H, O(1) + 0,(g)
The activation energy for this reaction is 75 kJ-mol. The enzyme catalase, found in blood, lowers the activation energy to
8.0 kJ-mol-1.
At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed
reaction at 25 °C?
T =
K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff32c3ee5-84ad-4b8f-a5ee-9f2098075ae5%2F4f87995b-72a5-415a-b2b0-acdea056a58a%2Fueofuoc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation
2Н,0, (aq)
2 H, O(1) + 0,(g)
The activation energy for this reaction is 75 kJ-mol. The enzyme catalase, found in blood, lowers the activation energy to
8.0 kJ-mol-1.
At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed
reaction at 25 °C?
T =
K
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