Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H,0,(aq) — 2н,00) + 0,(@) The activation energy for this reaction is 75 kJ-mol. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ-mol-1. At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °C? T = K

Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
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Chapter8: Reaction Rates And Equilibrium
Section: Chapter Questions
Problem 8.76E
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Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation
2Н,0, (aq)
2 H, O(1) + 0,(g)
The activation energy for this reaction is 75 kJ-mol. The enzyme catalase, found in blood, lowers the activation energy to
8.0 kJ-mol-1.
At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed
reaction at 25 °C?
T =
K
Transcribed Image Text:Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2Н,0, (aq) 2 H, O(1) + 0,(g) The activation energy for this reaction is 75 kJ-mol. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ-mol-1. At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °C? T = K
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