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Identify the Big-O (i.e. worst-case complexity) of each of the following blocks of code (assume the "stuff" being done is some constant time). n is the input size:

Identify the Big-O (i.e. worst-case complexity) of each of the following blocks of code (assume the "stuff" being done is some constant time). n is the input size:

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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3-9

Identify Big 0 of each loop.

Identify the Big-O (i.e. worst-case complexity) of each of the following blocks of code (assume the "stuff" being done is some constant time). n is the input size: [Select] O(n) for(int i=0; i<10*n; i++) { // do some stuff... for(int j=0; j<n-1; j++) { //do some other stuff... for(int k=0; k<10; k++) { // more stuff to do... } } } for(int i=n; i>0; i--) { // do some stuff... } for(int j-n; j>n; j--) { // do some stuff... } for(int k-n; k>n; k--) { // do some stuff... }
Transcribed Image Text:Identify the Big-O (i.e. worst-case complexity) of each of the following blocks of code (assume the "stuff" being done is some constant time). n is the input size: [Select] O(n) for(int i=0; i<10*n; i++) { // do some stuff... for(int j=0; j<n-1; j++) { //do some other stuff... for(int k=0; k<10; k++) { // more stuff to do... } } } for(int i=n; i>0; i--) { // do some stuff... } for(int j-n; j>n; j--) { // do some stuff... } for(int k-n; k>n; k--) { // do some stuff... }
[Select] [Select] [Select] for(int i=0; i<10000; i++) { // do some stuff... for (int j=0; j<10000; j++) { // do some other stuff... } } for (int i=1; i<n; i=i*2) { // do some stuff... } for (int i=0; i<2*n; i++) { // do some stuff... }
Transcribed Image Text:[Select] [Select] [Select] for(int i=0; i<10000; i++) { // do some stuff... for (int j=0; j<10000; j++) { // do some other stuff... } } for (int i=1; i<n; i=i*2) { // do some stuff... } for (int i=0; i<2*n; i++) { // do some stuff... }
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