In anticipation of an upcoming election, officials in Grand Ridge County are looking at the distance from each voter's home to that voter's nearest polling station.Assume that the population of all such distances for voters in Grand Ridge County is approximately normally distributed. An article for the newspaper PoliticallySound claimed that the mean of this population is 4.82 km. You want to test this claim, so you select a random sample of 22 Grand Ridge County voters, and foreach you record the distance the voter lives from their nearest polling station.Follow the steps below to construct a 90% confidence interval for the population mean of all the distances voters in Grand Ridge County live from their nearestpolling station. Then state whether the confidence interval you construct contradicts the reporter's claim. (If necessary, consult a list of formulas.)(a) Click on "Take Sample" to see the results for your random sample.escTake SampleSample size:Point estimate:0FISample standard deviation:0Critical value:0Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 90%confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute".ComputeExplanationCheckNumber of peopleF222000OOD F4Sample meanStandard error:Margin of error:4.971F590% confidence interval:F6AASample standarddeviationF72.433XCritical values0.005 2.8310.010-2.5180.025 -2.0800.050 1.721+333$2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | AccessibilityF8▶F9F104)F11D1امهM (b)Based on your sample, graph the 90% confidence interval for the population mean of all the distances the voters in Grand Ridge County live fromtheir nearest polling station.(c)Enter the values for the lower and upper limits on the graph to show your confidence interval.. For the point (), enter the claim 4.82 from the article.0.0000.0002,00090% confidence interval:4.0005.000Explanation6.000Does the 90% confidence interval you constructed contradict the claim made in the article?Choose the best answer from the choices below.8.000CheckSO No, the confidence interval does not contradict the claim. The mean of 4.82 km from the article is inside the 90%confidence interval.Yes, the confidence interval contradicts the claim. The mean of 4.82 km from the article is inside the 90%confidence interval.O No, the confidence interval does not contradict the claim. The mean of 4.82 km from the article is outside the 90%confidence interval.Yes, the confidence interval contradicts the claim. The mean of 4.82 km from the article is outside the 90%confidence interval.10.00010.0002022 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Accessibility

Question

In anticipation of an upcoming election, officials in Grand Ridge County are looking at the distance from each voter's home to that voter's nearest polling station.Assume that the population of all such distances for voters in Grand Ridge County is approximately normally distributed. An article for the newspaper PoliticallySound claimed that the mean of this population is 4.82 km. You want to test this claim, so you select a random sample of 22 Grand Ridge County voters, and foreach you record the distance the voter lives from their nearest polling station.Follow the steps below to construct a 90% confidence interval for the population mean of all the distances voters in Grand Ridge County live from their nearestpolling station. Then state whether the confidence interval you construct contradicts the reporter's claim. (If necessary, consult a list of formulas.)(a) Click on &#34;Take Sample&#34; to see the results for your random sample.escTake SampleSample size:Point estimate:0FISample standard deviation:0Critical value:0Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 90%confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select &#34;Compute&#34;.ComputeExplanationCheckNumber of peopleF222000OOD F4Sample meanStandard error:Margin of error:4.971F590% confidence interval:F6AASample standarddeviationF72.433XCritical values0.005 2.8310.010-2.5180.025 -2.0800.050 1.721+333$2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | AccessibilityF8▶F9F104)F11D1امهM (b)Based on your sample, graph the 90% confidence interval for the population mean of all the distances the voters in Grand Ridge County live fromtheir nearest polling station.(c)Enter the values for the lower and upper limits on the graph to show your confidence interval.. For the point (), enter the claim 4.82 from the article.0.0000.0002,00090% confidence interval:4.0005.000Explanation6.000Does the 90% confidence interval you constructed contradict the claim made in the article?Choose the best answer from the choices below.8.000CheckSO No, the confidence interval does not contradict the claim. The mean of 4.82 km from the article is inside the 90%confidence interval.Yes, the confidence interval contradicts the claim. The mean of 4.82 km from the article is inside the 90%confidence interval.O No, the confidence interval does not contradict the claim. The mean of 4.82 km from the article is outside the 90%confidence interval.Yes, the confidence interval contradicts the claim. The mean of 4.82 km from the article is outside the 90%confidence interval.10.00010.0002022 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Accessibility

Accepted Answer

Given that,
The population of all distances for voters in Grand Ridge country is approximately…