In C-language expression, how is not equal to represented? Select one: a. = b. all of the choices C. d. =! Determine the output of the given program code #include #include void main() { int n=1234, r=0, t; do { t=n%10; r=r*10+t; n=n/103; }while (n>0); printf("%d ", r); getch(); Select one: a. infinite loop b. 4321 c. 1234 d. none of the choices

In C-language expression, how is not equal to represented? Select one: a. = b. all of the choices C. d. =! Determine the output of the given program code #include #include void main() { int n=1234, r=0, t; do { t=n%10; r=r*10+t; n=n/103; }while (n>0); printf("%d ", r); getch(); Select one: a. infinite loop b. 4321 c. 1234 d. none of the choices

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter6: Modularity Using Functions

Section6.4: A Case Study: Rectangular To Polar Coordinate Conversion

Problem 9E: (Numerical) Write a program that tests the effectiveness of the rand() library function. Start by...

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#include <stdio.h>int main(){int i, j, k=0;for (i=1; i<3; i++){for (j=1; j<3; j++){k = i+j;printf("Value of k is %d\n" ,k);}}printf("Value of k is %d\n",2*k);return 0;} how do you modify this code so k only prints even numbers
#include <stdio.h> int main(){ int arr[10]; int i; for (i=0; i<10; i++){ arr[i] = i; } for (i=0; i<10; i++){ printf("arr[%d] = %d\n", i, arr[i]); } return 0;} Copy the code and modify it as follows: Add another separate array of 10 integers. The following code parts are to be added (in the same order as specified) after the printing of the values of the first array:(1) Copy the content of the first array to the second array. Add 10 to each of the values of the second array. Make use of a single loop to achieve this part.(2) Print each element of the second array. Make use of another loop for this part
#include <stdio.h>int main(){int d;int s[20],i, r, p, lg=0,m;char c;printf("Enter number of salesman(max 20): ");scanf("%d", &d);for(i=0; i<d; i++){ printf("\n salesman %d sales: ");scanf("%d", &s[i]);}for(i=0; i<d; i++){for(r=i+1; j<d; r++){if(s[i] > s[r]){p= s[i];s[i] = s[r];s[j] = p;}}}printf("\nsalesman lowest to highest: ");for(i=0; i<d; i++){printf("%d\t", s[i]);}for(i=0;i<m;i++){printf("\n highest sales: %d ",lg);if(lg<=s[i])lg=s[i];break;}getch();} >>> the upper part output should be like this enter number of salesman (max 20): 5 salesman 1 500 salesman 2 300 salesman 3 1000 salesman 4 200 salesman 5 1000 in the lower part the lowest to highest the output should become like this salesman 4 200 salesman 2 300 salesman 1 500 salesman 3 1000 salesman 5 1000 highest total sales : 2000
#include<stdio.h> #include<stdlib.h> main() { int m, sum = 0, counter = 0; int first = 2147483647, second = 2147483647, third = 2147483647, min = 2147483647; double average;printf("Enter an int or -1 to stop:\n"); while (1) {scanf_s("\n%d", &m);if (m == -1) { break; } sum = sum + m; counter++; if (m < first first == second first == third ) { third = second; second = first; first = m; } else if (m < second && m !=first ) { third = second; second = m; } else if (m < third && m != second) { third = m; } else if (first == second == third) { printf("min is: %d", first); }}printf("Sum of value: %d \n", sum); average =(double) sum /(double)counter; printf("Avarege is: %.2lf \n", average); printf("First min is: %d\n", first); printf("Second min is: %d\n", second); printf("Third min is: %d\n", third);system("pause"); } can you run this code please
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