In Fig. the loop is being pulled to the right at constant speed v.A constant current I flows in the long wire, in the direction shown.b1.Do this two ways:Calculate the magnitude of the net emf induced in the loop.3.a. by using Faraday's law of induction (Hint: See Exercise 29.7) and,b. by looking at the emf induced in each segment of the loop due to its motion.2. Find the direction (clockwise or counterclockwise) of the current induced in the loop.Do this two ways:a. using Lenz's law andb. using the magnetic force on charges in the loop.Check your answer for the emf in part (a) in the following special cases to see whether it isphysically reasonable:a. The loop is stationary:b. The loop is very thin, so a->0,C. The loop gets very far from the wire.

Answered: Image /qna-images/answer/50830f9c-193f-4fb8-aaf3-d8f2aa3b9e47.jpg

In Fig. the loop is being pulled to the right at constant speed v. A constant current I flows in the long wire, in the direction shown. b 1. Calculate the magnitude of the net emf E induced in the loop. Do this two ways: 2. a. by using Faraday's law of induction (Hint: See Exercise 29.7) and, b. by looking at the emf induced in each segment of the loop due to its motion. Find the direction (clockwise or counterclockwise) of the current induced in the loop.

In Fig. the loop is being pulled to the right at constant speed v. A constant current I flows in the long wire, in the direction shown. b 1. Calculate the magnitude of the net emf E induced in the loop. Do this two ways: 2. a. by using Faraday's law of induction (Hint: See Exercise 29.7) and, b. by looking at the emf induced in each segment of the loop due to its motion. Find the direction (clockwise or counterclockwise) of the current induced in the loop.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter13: Electromagnetic Induction

Section: Chapter Questions

Problem 58P: The square armature coil of an alternating current generator has 200 turns and is 20.0 cm on side....

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