In guinea pigs, the allele for short hair is dominant. If all the guinea pigs are born short haired what are the possible genotypes of the parents? (There are two possible combinations.) Show the answers with punnett square
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In guinea pigs, the allele for short hair is dominant. If all the guinea pigs are born short haired what are the possible genotypes of the parents? (There are two possible combinations.) Show the answers with punnett square
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- In guinea pigs, the black coat (B) is dominant over the white coat (b), and straight hair (H) is dominant over curly hair (h). Using a Punnett square, complete the cross between a heterozygous black, curly-haired individual and a homozygous straight-haired, white individual. State the parent genotypes and gametes, and the F1 phenotypes and genotypes.A woman and a man have a red-green colorblind daughter. What can you say about the genotypes of the parents? Be specific and complete, using correct conventional notation.Using the pedigree chart attached: Above is a pedigree for colorblindness. Based on the pedigree, is the disease dominant or recessive and is it sex-linked or autosomal? Why? Furthermore, what is the probability that 18 on this chart is affected but the condition, and what is the probability that 18 is a carrier? Why? Are the probability of being a carrier and an affected individual different? Why?
- Imagine you have a blood group of "X" which is recessive and expressed by xx. The dominant blood groups are Y and Z, where homozygous of these alleles are expressed as YY and ZZ, respectively. What will be the genotype of your parents blood group? Why? Please explain in your own words. [Max 200 words]in humans brown eyes (B) are dominant over blue (b).A brown eye man marries a blue-eyed woman and they have three children , two of whom are brown eyed and one of whom is blue eyed.Draw the punnett square that illustrate this marrage.what is the man's genotype ? what are the genotype of the children?The allele for albinism ( c ) is recessive to the allele for normal pigmentation ( C ). A normally pigmented woman whose father is an albino marries an albino man whose parents are normal. They have three children, two normal and one albino. Give the genotypes for EACH person listed.
- In humans, Widow’s peak (W) is dominant over a continuous hairline (w), and short fingers (F) are dominant over long fingers (f). Two individuals with widow’s peaks and short fingers have a child with a continuous hairline and long fingers. Determine the genotype of the parents.In guinea pigs, black fur is dominant over brown fur, and short hair is dominant over long hair. These traits follow Mendelian inheritance. Suppose a homozygous short black hair is mated with a homozygous long brown haired rabbit, determine the phenotypic ratio of the following: F1 generation; F2 generation; F1 mated with a short brown haired rabbit. Gene Notation: B - hair color , S - hair lengthIn addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry. What is the phenotype of the male parent? What is the phenotype of the female parent? Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio. Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.