In the d part of this solution , for the electrical bandwidth we are getting a negative value , but here you have written a positive value. Please explain.
In the d part of this solution , for the electrical bandwidth we are getting a negative value , but here you have written a positive value. Please explain.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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In the d part of this solution , for the electrical bandwidth we are getting a negative value , but here you have written a positive value. Please explain.
Transcribed Image Text:Step2
b)
0.315 W
- = 0.033 W
x10-9)
atio.
log(#8) - 10log (8
P(w))
9.87
0.315
electrical andwidth
= v2 × 9.87 :
ANSWER
Output power at frequency
P(w) = 0.033 W
electrical bandwidth in ratio form
optical bandwidth in ratio form
1:
Transcribed Image Text:3. ) Estimate the optical loss due to Fresnel reflection at a fiber core from GaAs
each of refractive indices 1.48 and 3.5 respectively.
b) Calculate the optical power emitted into air for the device, when the step
index fiber has a numerical aperture of 0.16, coupled power of 0.31 mW.
c) Determine the overall power conversion efficiency for the LED if it is
operating with a drive current of 210 mA and a forward voltage of 1.5V.
d) Find the optical output power at 170MHZ, and calculate the optical and
electrical modulation bandwidth for a minority carrier recombination life time
of 9ns.
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