#include #include Collapse 3 4 void Loop(int n) { int i = n; Exercise 6.1 5- 6 7 while (i > 1) Take a look at the code to the left. { printf ("%i\n",i); if (i%2 == 0) { i = i/2; Construct a table that shows the value of the variables i and n _2 3 4 } during the execution of the program. The table contains one column else for each variable and one line for each iteration. { i = i+l; 6 L7 _8 } Drag from here } } n=10 . i-10 int main (void) { 23 24 25 n=10 . i=3 Loop (10); return EXIT_SUCCESS; } n=10 . i=1 n=10 . i=6 n=10 . i=5 n=10 . i=4 n=10 . i=2 Construct your solution here Check It!

#include #include Collapse 3 4 void Loop(int n) { int i = n; Exercise 6.1 5- 6 7 while (i > 1) Take a look at the code to the left. { printf ("%i\n",i); if (i%2 == 0) { i = i/2; Construct a table that shows the value of the variables i and n _2 3 4 } during the execution of the program. The table contains one column else for each variable and one line for each iteration. { i = i+l; 6 L7 _8 } Drag from here } } n=10 . i-10 int main (void) { 23 24 25 n=10 . i=3 Loop (10); return EXIT_SUCCESS; } n=10 . i=1 n=10 . i=6 n=10 . i=5 n=10 . i=4 n=10 . i=2 Construct your solution here Check It!

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter7: Arrays

Section: Chapter Questions

Problem 4PP: (Numerical) Write and test a function that returns the position of the largest and smallest values...

See similar textbooks

Similar questions

(Numerical) Write and test a function that returns the position of the largest and smallest values in an array of double-precision numbers.
CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;
a) Write a program that asks user to enter number of vertices in an undirected graph and then the adjacency matrix representing the undirected graph. The program, then, must display whether the given graph is connected or not. You will find two sample runs of the program below. Sample 1 Sample 2 Enter number of vertices: 3 Enter number of vertices: 3 Enter adjacency matrix: 0 1 1 1 0 0 1 0 0 Enter adjacency matrix: 0 1 0 1 0 0 0 0 0 The graph is connected. The graph is not connected.
#include <stdio.h>int main(){int d;int s[20],i, j, p, lg=0,m,t=0;char c;printf("Enter number of sale: ");scanf("%d", &d);for(i=0; i<d; i++){ printf("\n sales %d sales: ",i+1);scanf("%d", &s[i]);}for(i=0; i<d; i++){for(j=i+1; j<d; j++){if(s[i] > s[j]){p= s[i];s[i] = s[j];s[j] = p;}}}printf("\n sales lowest to highest: ");for(i=0; i<d; i++){printf("\nsales %d ", s[i]);}printf("\n highest: %d ",t);getch();} it should be: highest : 2000
#include <stdio.h>int main(){int d;int s[20],i, r, p, lg=0,m;char c;printf("Enter number of salesman(max 20): ");scanf("%d", &d);for(i=0; i<d; i++){ printf("\n salesman %d sales: ");scanf("%d", &s[i]);}for(i=0; i<d; i++){for(r=i+1; j<d; r++){if(s[i] > s[r]){p= s[i];s[i] = s[r];s[j] = p;}}}printf("\nsalesman lowest to highest: ");for(i=0; i<d; i++){printf("%d\t", s[i]);}for(i=0;i<m;i++){printf("\n highest sales: %d ",lg);if(lg<=s[i])lg=s[i];break;}getch();} >>> the upper part output should be like this enter number of salesman (max 20): 5 salesman 1 500 salesman 2 300 salesman 3 1000 salesman 4 200 salesman 5 1000 in the lower part the lowest to highest the output should become like this salesman 4 200 salesman 2 300 salesman 1 500 salesman 3 1000 salesman 5 1000 highest total sales : 2000
Python question Application: Python Fragment Formulation (Q1 – Q4) In this group of questions you are asked to produce short pieces of Python code. When you are asked to "write a Python expression" to complete a task, you can either give the expression in one line or break down the task into several lines. The last expression you write must represent the required task. Question 1 (Reduce parentheses) Give an equivalent version of this expression by removing as many redundant parentheses as possible, without expanding the brackets or simplifying. (x**(2**y))+(y*((z+x)**3)) Question 2 (Translate arithmetic concept into Python) You are given a list of numbers, named numbers, containing 3 integers. Write a python expression (one line) that evaluates to True if and only if the product of any two numbers in the given list is greater than the sum of all three numbers. Note: the product of two numbers, x and y is x*y. Question 3 (List/table access) You are given a table,…
2- Write a function sumsteps2 that calculates and returns the sum of 1 to n in steps of 2, where n is an argument passed to the function. For example, if 11 is passed, it will return 1 + 3 + 5 + 7+ 9 + 11. Do this using a for loop. Calling the function will look like this: >> sumsteps2 (11) ans = 36
C++ Vector iteration: Sum of excess. Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8.
04: (A) what is the number of iterations in the following for loop? cin>>n; for (int i 1; i< n; i++){ couteci;
#include<iostream>using namespace std;//swappingvoid swapping(int &a, int &b) { //variable declaration int temp;//swapping temp = a; a = b; b = temp;}//to display the arrayvoid display(int *array, int s) { //Loop for(int x = 0; x<s; x++) //Creating the array cout << array[x] << " "; cout << endl;}//Performing the selectionSortvoid selectionSort(int *array, int s) { //variable declaration int x, j, min; //loop for(x = 0; x<s-1; x++) { //used to minimum data min = x; for(j = x+1; j<s; j++) if(array[j] < array[min]) min = j; //placing the value swap(array[x], array[min]); }}//main of the codeint main() { //variable declaration int n; //input cout << "Enter the number of elements: "; //Storing the input cin >> n; //Creating array int arr[n]; //Asking for the array value cout << "Enter elements:" << endl;…
#include <stdio.h> int main(){ int a; /* for loop execution */ for ( a = 1; a <= 100; a++){ printf("%d\n",a * a); } return 0; } write a code using while loop that will provide the same output as the code given above.
English (e what is the output of the following program? #include int test (int &, int); main () { int a=10, b=15; test (b, a); test (a,b); cout<