In(n) n 3. For all n > 2, 4. For all n > 2,<, 5. For all n > 1, n ln(n) 6. For all n > 2,2²8 >, and the series Σ n and the series 2 , and the series 2 and the series n², 72 diverges, so by the Comparison Test, the series - In(n) converges, so by the Comparison Test, the series conve (n) diverge diverges, so by the Comparison Test, the series converges, so by the Comparison Test, the series Σ converge diverges.
In(n) n 3. For all n > 2, 4. For all n > 2,<, 5. For all n > 1, n ln(n) 6. For all n > 2,2²8 >, and the series Σ n and the series 2 , and the series 2 and the series n², 72 diverges, so by the Comparison Test, the series - In(n) converges, so by the Comparison Test, the series conve (n) diverge diverges, so by the Comparison Test, the series converges, so by the Comparison Test, the series Σ converge diverges.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 49E
Related questions
Question
Compassion Test Problem 5
![Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test
(NOT the Limit Comparison Test.) For each statement, enter C (for "correct") if the argument is valid, or enter I (for "incorrect") if any
part of the argument is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter I.)
1. For all n > 2,
2. For all n> 1,
3. For all n > 2,
4. For all n > 2,
5. For all n > 1,
6. For all n > 2,
In(n)
6-n'
In(n)
3
n³_1
1
n In (n)
1
n²-8
2
n²
22
n
and the series Σ
and the series
and the series
and the series 2
Σ
and the series 2
and the series
-
n
converges, so by the Comparison Test, the series
converges, so by the Comparison Test, the series
diverges, so by the Comparison Test, the series >
In(n)
converges, so by the Comparison Test, the series
>
n²
= diverges, so by the Comparison Test, the series
converges, so by the Comparison Test, the series
n
converges.
3 converges.
diverges.
6-n³
converges.
n³-1
(n) diverges.
converges.
1
n²-8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdd3494d7-16cb-4f96-a1a3-f69334a1e65b%2Feeeb3d70-0d3e-4071-9d1c-96425013e85a%2Fqj3zobs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test
(NOT the Limit Comparison Test.) For each statement, enter C (for "correct") if the argument is valid, or enter I (for "incorrect") if any
part of the argument is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter I.)
1. For all n > 2,
2. For all n> 1,
3. For all n > 2,
4. For all n > 2,
5. For all n > 1,
6. For all n > 2,
In(n)
6-n'
In(n)
3
n³_1
1
n In (n)
1
n²-8
2
n²
22
n
and the series Σ
and the series
and the series
and the series 2
Σ
and the series 2
and the series
-
n
converges, so by the Comparison Test, the series
converges, so by the Comparison Test, the series
diverges, so by the Comparison Test, the series >
In(n)
converges, so by the Comparison Test, the series
>
n²
= diverges, so by the Comparison Test, the series
converges, so by the Comparison Test, the series
n
converges.
3 converges.
diverges.
6-n³
converges.
n³-1
(n) diverges.
converges.
1
n²-8
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