Ip=12 A Re www 13 Ω + aVL For the transformer equivalent circuit shown what is the source voltage (Vg = ?) a. 3096 +j156 V b. 3036 + 1216 V c. No right answer d. 876 +j156 V X₂ moo 18 Ω a²R₁ = (4)(602) = 240 Ω

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.61P
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Ip = 12 A
Re
ww
13 Ω
+
aVL
a²R₁
For the transformer equivalent circuit shown what is the source voltage (Vg = ?)
a. 3096 +j156 V
b. 3036 + 1216 V
c. No right answer
d. 876 +j156 V
Xe
moo
18 Ω
= (4)(60 Ω) = 240 Ω Ω
Transcribed Image Text:Ip = 12 A Re ww 13 Ω + aVL a²R₁ For the transformer equivalent circuit shown what is the source voltage (Vg = ?) a. 3096 +j156 V b. 3036 + 1216 V c. No right answer d. 876 +j156 V Xe moo 18 Ω = (4)(60 Ω) = 240 Ω Ω
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