It follows that for every integer k ≥ 1, 4bk- k-1 = Thus, bo, b₁,b₂, Need Help? 4k-1-3 4k x Read It x X ) by substitution from (*)✔✔ by basic algebra ... satisfies the given recurrence relation. D by substitution from (*)✓✓✓.
It follows that for every integer k ≥ 1, 4bk- k-1 = Thus, bo, b₁,b₂, Need Help? 4k-1-3 4k x Read It x X ) by substitution from (*)✔✔ by basic algebra ... satisfies the given recurrence relation. D by substitution from (*)✓✓✓.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.6: Inequalities
Problem 80E
Related questions
Question
![[5/15 Points]
DETAILS
Let k be any integer with k 2 1. Substitute k and k-1 in place of n, and apply the definition of bo, b₁,b₂.
1'
b₁ = 4k (*) and
(**) for every integer k ≥ 1.
Let b, b, b,... be defined by the formula b
be defined by the formula b,, = 4" for every integer n 2 0. Fill in the blanks to show that bo, b₁,b₂, ... satisfies the recurrence relation b₁ = 4bk-1
for every integer k ≥ 1.
1'
= 4
=
45°F
Temps drop
It follows that for every integer k ≥ 1,
k-1
4bk-1
=
Need Help?
PREVIOUS ANSWERS
Submit Answer
7. [8.3/20 Points]
bk-1²
4k-1-3
4k
=
Read It
4
DETAILS
X
X
X
Thus, bo, b₁,b₂,... satisfies the given recurrence relation.
1'
)
X
EPPDISCMATH5 5.6.010.
by substitution from (*)✔
by basic algebra
by substitution from (*)✓✓✓.
PREVIOUS ANSWERS
H Q Search
↳
EPPDISCMATH5 5.6.014.
k
MY NOTES
to both b and bk - 1¹
MY NOTES
ASK YOUR TEACHER
The result is
ASK YOUR TEACHER
12:09 PM
11/9/2029
C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2dd91b83-9757-4690-9b37-5d4650824402%2F19b806af-ba1a-4bd0-b917-3699a180d043%2F754royl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[5/15 Points]
DETAILS
Let k be any integer with k 2 1. Substitute k and k-1 in place of n, and apply the definition of bo, b₁,b₂.
1'
b₁ = 4k (*) and
(**) for every integer k ≥ 1.
Let b, b, b,... be defined by the formula b
be defined by the formula b,, = 4" for every integer n 2 0. Fill in the blanks to show that bo, b₁,b₂, ... satisfies the recurrence relation b₁ = 4bk-1
for every integer k ≥ 1.
1'
= 4
=
45°F
Temps drop
It follows that for every integer k ≥ 1,
k-1
4bk-1
=
Need Help?
PREVIOUS ANSWERS
Submit Answer
7. [8.3/20 Points]
bk-1²
4k-1-3
4k
=
Read It
4
DETAILS
X
X
X
Thus, bo, b₁,b₂,... satisfies the given recurrence relation.
1'
)
X
EPPDISCMATH5 5.6.010.
by substitution from (*)✔
by basic algebra
by substitution from (*)✓✓✓.
PREVIOUS ANSWERS
H Q Search
↳
EPPDISCMATH5 5.6.014.
k
MY NOTES
to both b and bk - 1¹
MY NOTES
ASK YOUR TEACHER
The result is
ASK YOUR TEACHER
12:09 PM
11/9/2029
C
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