3b. An additional gene, called W, is found that affects the synthesis of enzymes 1 and 2. Mutantd has a recessive mutation in gene W.genotypeenzyme activitywithout fictamine1with fictamine12strainWXYZ2wild-type ++++++mutant a++mutant bmutant cmutant d+++++T++++++++11+!++++++1++!!!++ iv) The phenotype of a double mutant, W X, is shown below. Choose the single regulatoryscheme above that is consistent with all of the data. Explain your answer briefly.enzyme activitygenotypewithout fictaminewith fictaminestrainWXY22mutant 5++++++++++-

Name: 3b. An additional gene, called W, is found that affects the synthesis
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Description: 3b. An additional gene, called W, is found that affects the synthesis of enzymes 1 and 2. Mutantd has a recessive mutation in gene W.genotypeenzyme activitywithout fictamine1with fictamine12strainWXYZ2wild-type ++++++mutant a++mutant bmutant cmutant

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iv) The phenotype of a double mutant, W X, is shown below. Choose the single regulatory scheme above that is consistent with all of the data. Explain your answer briefly. enzyme activity genotype without fictamine 2 with fictamine 2 strain W X Y Z 1 1 mutant 5 + + ++ ++ ++ ++

iv) The phenotype of a double mutant, W X, is shown below. Choose the single regulatory scheme above that is consistent with all of the data. Explain your answer briefly. enzyme activity genotype without fictamine 2 with fictamine 2 strain W X Y Z 1 1 mutant 5 + + ++ ++ ++ ++

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter18: Dna Technologies: Making And Using Genetically Altered Organisms, And Other Applications

Section: Chapter Questions

Problem 7TYK: Which of the following is not true of somatic cell gene therapy? a. White blood cells can be used....

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draw the p21 promoter in a cell without E2F
An additional gene, called W, is found that affects the synthesis of enzymes 1 and 2. Mutant d has a recessive mutation in gene W. genotype enzyme activity without fictamine with fictamine 1 strain W X Y 1 2 2 wild-type + ++ ++ mutant a + mutant b + mutant c + + + mutant d + + ++ Once again, justify each answer in one sentence. i) Is gene W most likely a positive or a negative regulator? ii) Is the activity of W activated or inactivated by the presence of fictamine? + + + + Z + + + + ++ ++ H ++ ++ ! 1 ++
g protein D. Growth factor receptor ng Tool 0 Q ing C. Growth factor-binding protein D. Growth factor receptor E. Transcription activator A child with retinoblastoma is found to have a 13q14 deletion. The Rb gene, which resides at this locus, produces which kind of tumor-associated protein? A. Cell cycle regulator B. Growth factor ㅂ분 요 9 12 W □ @ 2 C Edit in Paint 8 60 8 Focus
a. What is your epigenome (i.e. epigenetics)? b. Does lifestyle affect your epigenome? Explain -c. Does your epigenome change with age? Explain d. What is epigenetic therapy? Is it working? Explain Edit View Insert Format Tools Table 12pt v Paragraph v в I Address DELL F7 F8 F9 F10 F1 F4 F5 F6 # % & 3 4 6. 7 8 9 Y ...
ocument/d/1J-wo90GpYsd_jQSUBtDQHWisqGvSOteUQYoXaXazyS0/edit uction to cell.. R 1 Summary of Philo... E Petrona Andres Mig.. 2 Translations IXL: Par... IXL - Translations: g.. 1 IXL- meostasis Lab Exercise Tools Add-ons Help Last edit was 2 days ago text Calibri 12 BIU Conclusion: 1. List the changes you observed in the body color and perspiration level in response to? 2. Explain how the changes help the body adjust to maintain equilibrium (homeostasis)? 3. Speculate why a change in body temperature occurs? 4. Name which mechanisms your body uses to maintain a constant body temperature? 5. Explain why an increased breathing rate accompanies exercise? 6. Explain why an increased heart rate accompanies exercise? 7. Write a paragraph about the conclusions you can draw about your body's ability to maintain equilibrium (homeostasis). Be sure to include the answers to the questions above.
O The lac operon in E.coli encodes enzymes necessary for the breakdown of lactose. For each enzyme (lac Z and lac Y), indicate with a + or-whether or not it is made when there is no lactose or when there is lactose. B-galactosidase (lac Z) No Lactose Permease (lac Y) Lactose Lactose No Lactose Genotype PP0 Z Y/I P*O*Z•Y* I'POCZ Y*/I P* O©Z*Y° P O Z'Y/I P'OʻZ'Y* PP O ZY*/IP*O*Z*Y* IP OCZ Y /I P*O*Z•Y* IPO ZY*/I* P*O©Z*Y• I'PO*Z Y*/IP'O*Z*Y°
e B 1_30*_SP23 - General Biology I (for majors)/11364 of € 2 A us page X F1 What conditions would we find on the gene of a prokaryote if there is low amounts of tryptophan within the cytoplasm? Select one: a. lactose would attach to the repressor removing it from the promoter promoting the transcription of lactase b. no repressor is on the promoter creating constant transcription of lactase c. tryptophan would attach to the repressor removing it from the promoter promoting the transcription of lactase O d. repressors would bind to the promoter stopping the transcription of lactase e. lactose would attach to the repressor removing it from the promoter promoting the transcription of tryptophan producing enzymes no repressor is on the promoter creating constant transcription of tryptophan producing enzymes tryptophan would attach to the repressor binding it to the promoter and stopping the transcription of tryptophan producing enzymes O f. O g. 2 Oh. tryptophan would attach to the…
You are in charge of a new gene therapy clinic. Two cases have been referred to you for review and possible therapy. Case 1. A mutation in the promoter of a proto-oncogene causes the gene to make too much of its normal product, a receptor protein that promotes cell division. The uncontrolled cell division has caused cancer. Case 2. A mutation in an exon of a tumor-suppressor gene makes this gene nonfunctional. The product of this gene normally suppresses cell division. The mutant gene cannot suppress cell division, and this has led to cancer. What treatment options can you suggest for each case?
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draw the p21 promoter in a cell with E2F
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Match each example of mutation to the correct effect on function. Hypomorphic mutation Hypermorphic mutation Antimorphic mutation Neomorphic A deletion results in the loss of part of a protein and the protein retains some of its normal activity. A mutant allele makes a protein with increased cataytic activity. A mutant form of a transcription factor binds new DNA sequences to activate different genes. A mutant from of a receptor protein interferes with the function of the wild-type receptor through heterodimerization.