length life with normal distribution, and a standard deviation of o = 10 hours. A sample of size n = 100 is obtained, and its sample mean is calculated to be 400 hours. Find the 99% confidence interval for the average length life fl. = 397.424 U < 402.576 x invalid interval notation. Find the upper 99% bound for the average length life μl. 402.576 397.424 x invalid interval notation. Find the lower 99% bound for the average length life fl. x invalid interval notation. Give your answer as intervals. Use - and too if needed

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