Let F be a field and let p(x) ∈ F[x]. If f(x), g(x) ∈ F[x] anddeg f(x) < deg p(x) and deg g(x) < deg p(x), show that f(x)+<p(x)> = g(x)+ <p(x)> implies f(x) =g(x).
Let F be a field and let p(x) ∈ F[x]. If f(x), g(x) ∈ F[x] anddeg f(x) < deg p(x) and deg g(x) < deg p(x), show that f(x)+<p(x)> = g(x)+ <p(x)> implies f(x) =g(x).
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.1: Polynomial Functions Of Degree Greater Than
Problem 36E
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Let F be a field and let p(x) ∈ F[x]. If f(x), g(x) ∈ F[x] and
deg f(x) < deg p(x) and deg g(x) < deg p(x), show that f(x)+
<p(x)> = g(x)+ <p(x)> implies f(x) =g(x).
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