Let f(x) be a function that has a Taylor Series centred at x = 3 given by f(κ) = Σ (241) (= - 4 2 +2 converges. What is the smallest value of k for which the derivative f(*) (4) * 0? k = 6 What is the value of this derivative? f)(4) = 0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 50E
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Let f(x) be a function that has a Taylor Series centred at x = 3 given by
DO 3^n²
f(x)=
-(x-4)²n+2
converges.
n2=2
(2n + 1)!
What is the smallest value of k for which the derivative f(*) (4) * 0? k = 6
What is the value of this derivative? f(*) (4) = 0
Transcribed Image Text:Let f(x) be a function that has a Taylor Series centred at x = 3 given by DO 3^n² f(x)= -(x-4)²n+2 converges. n2=2 (2n + 1)! What is the smallest value of k for which the derivative f(*) (4) * 0? k = 6 What is the value of this derivative? f(*) (4) = 0
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