On line A. How did you add the 2 equations to get 3R on the bottom?On line B. How did you subtract the 2 equations to get 6R on the bottom? Step 1magnetic field at the center of circular coilB= Hol/2rStep 2lo IMo I4(31)= 0-33-EBI =lo I3 Ylo IMo I62=4 (3Y)6 Yuo IMo Ilo I%3D4- YHof= 0:4375 F4 Y16 Y QuestionFigure 29-27 shows three circuits consisting of straight radial lengths and concentric circular arcs(either half- or quarter-circles of radii r, 2r, and 3r). The circuits carry the same current. Rank themaccording to the magnitude of the magnetic field produced at the center of curvature (the dot),greatest first.(a)(b)()

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Answered: line A. How did you add the 2 equations…

line A. How did you add the 2 equations to get 3R on the bottom? On line B. How did you subtract the 2 equations to get 6R on the bottom

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 35P

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Question

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On line A. How did you add the 2 equations to get 3R on the bottom? On line B. How did you subtract the 2 equations to get 6R on the bottom?

Step 1
magnetic field at the center of circular coil
B= Hol/2r
Step 2
lo I
Mo I
4(31)
= 0-33-E
BI =
lo I
3 Y
lo I
Mo I
62=
4 (3Y)
6 Y
uo I
Mo I
lo I
%3D
4- Y
Hof
= 0:4375 F
4 Y
16 Y

Question
Figure 29-27 shows three circuits consisting of straight radial lengths and concentric circular arcs
(either half- or quarter-circles of radii r, 2r, and 3r). The circuits carry the same current. Rank them
according to the magnitude of the magnetic field produced at the center of curvature (the dot),
greatest first.
(a)
(b)
()

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