lmine the rate law for the production of nitrosyl fluoride (NO,F) that occurs according to the following balanced chemical equation: 2 NO, (g) + F2 (g) > 2 NO,F (B) The following data were obtained from varying the concentrations of the reactants: [NO.) (M) 0.00130 0.00259 Initial Rate (M/s) 2.16 х 101 4.30 x 104 2.61 х 104 5.22 x 10 [F] (M) Run 1 0.00479 Run 2 0.00479 Run 3 0.00612 0.00123 Run 4 0.00612 0.00246 (A) Rate = k (NO] [F2] Rate = k (NO2)'(Fa] Rate = k (NO2) Rate - k (NO,J'(F]05 Rate = k (NO2] [F10s (E)
lmine the rate law for the production of nitrosyl fluoride (NO,F) that occurs according to the following balanced chemical equation: 2 NO, (g) + F2 (g) > 2 NO,F (B) The following data were obtained from varying the concentrations of the reactants: [NO.) (M) 0.00130 0.00259 Initial Rate (M/s) 2.16 х 101 4.30 x 104 2.61 х 104 5.22 x 10 [F] (M) Run 1 0.00479 Run 2 0.00479 Run 3 0.00612 0.00123 Run 4 0.00612 0.00246 (A) Rate = k (NO] [F2] Rate = k (NO2)'(Fa] Rate = k (NO2) Rate - k (NO,J'(F]05 Rate = k (NO2] [F10s (E)
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section11.1: Reaction Rate
Problem 11.3CE
Related questions
Question
![termine the rate law for the production of nitrosyl fluoride (NO,F) that occurs according to the following
balanced chemical equation:
9)
2 NO: (E) + F2 (g) > 2 NO,F (g)
The following data were obtained from varying the concentrations of the reactants:
[NO.) (M)
[F-] (M)
Initial Rate (M/s)
Run 1
0.00130
0.00479
2.16 x 10
Run 2
0.00259
0.00479
4.30 x 104
2.61 x 101
5.22 x 10
Run 3
0.00612
0.00123
Run 4
0.00612
0.00246
(A)
(B)
Rate = k [NO] [F2]
Rate = k [NO2)'(F2]
Rate = k (NO2)
Rate = k (NO:]?(F]05
Rate = k [NO2)] (F:10.5
(E)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5a3df371-d475-482a-84ce-057c931f1fc6%2F6bec6182-6df2-4df0-8d94-8ce3e2845b7a%2Fic1e8z_processed.jpeg&w=3840&q=75)
Transcribed Image Text:termine the rate law for the production of nitrosyl fluoride (NO,F) that occurs according to the following
balanced chemical equation:
9)
2 NO: (E) + F2 (g) > 2 NO,F (g)
The following data were obtained from varying the concentrations of the reactants:
[NO.) (M)
[F-] (M)
Initial Rate (M/s)
Run 1
0.00130
0.00479
2.16 x 10
Run 2
0.00259
0.00479
4.30 x 104
2.61 x 101
5.22 x 10
Run 3
0.00612
0.00123
Run 4
0.00612
0.00246
(A)
(B)
Rate = k [NO] [F2]
Rate = k [NO2)'(F2]
Rate = k (NO2)
Rate = k (NO:]?(F]05
Rate = k [NO2)] (F:10.5
(E)
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