Locate the center of gravity of the two-block assembly. The specific weights of the materials A and B are YA and YB = 400 lb/ft³, respectively. = 150 lb/ft³ Hint: Look at your units. This the center of gravity (weight) distances will be solved using the first moment of weight Σwixi divided by the total weight Σwi. uzu? 89*7 = 'u? = x 2 in. x 6 in. 6 in. B y 2 in. 6 in.
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- The equation of the catenary shown is y = 100 cosh (x/100) where x and y are measured in feet (the catenary is the shape of a cable suspended between two points). Locate the y-coordinate 0f the centroid of the catenary by numerical integration using x=25ft.Compute the coordinates of the centroid (,) of the area shown. Also compute the area moment of intertia about the x' and y' axes with origin at the centroid. ур C + 2013 Michael Swanbom cc 10 BY NC SA a*b* - a a → x Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 41 cm b 25 cm с 50 cm The x coordinate of the centroid is = cm. The y coordinate of the centroid is y cm. The moment of inertia about the x' axis going through the centroid is I' The moment of inertia about the y' axis going through the centroid is I✓ cm4. cm4.In civil construction it is very common to use L sections, angle, for comer pillars. Calculate the center of gravity L drawn below, informing the x coordinates with respect to the y axes and the Moment of Inertia Ix and Iy with respect to this center of gravity. Consider as measurements in centimeters, where: = 60 b= 90 Note: use Steiner's theorem 50 a 20
- 50 mm 150 mm 150 mm 300 mm find the moment of inertia for this exercise, with the following formulas: Polar Jo= Iox + + Toy Iox - Icx + Adg² Toy = Icg + dobe ² Caculation of centroid attached below. use it to solve the question in red box asap Som Av 3com for Portion A₁ - the figure is symme about y-aris. 2=0. AL 120mm AALD Area of A₁ = 300x50 = 15000 Y₁ = y₁ y = 300 for Pation A2 Area Az = 50x300 = 15000 By Considering Centroid, from the Bottom of the section. 300+ 50 = ₁ + 3/2 = 325 Centroid (ā, y) = = [0₁ SE = 50mm A, Ya+ A₂4 0, A₁+A₂ 15000x150 +15000x325 15000 15000 (0.237.5)Compute the coordinates of the centroid (x, y) of the area shown. Also compute the area moment of intertia about the x' and y' axes with origin at the centroid. C a *b*a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 40 cm 23 сm 49 cm The x coordinate of the centroid is x cm. The coordinate of the centroid is y cm. The moment of inertia about the x' axis going through the centroid is I,' cm4. The moment of inertia about the y' axis going through the centroid is I," cm4.Compute the moment about point A. Use F1-800 lb, F2-50 lb and F3-1200 lb. Show all work on your paper to receive credit. With your written final answer, include 3 significant digits, units and a direction arrow. -251- 3h 201 Fi Type your answer for the moment about A below with 3 significant digits. Do not type units with your numeric answer. -2.5 ft- -3 ft- B F₂ 2 ft 4 ft A B 45° F3
- Compute the coordinates of the centroid (a, g) of the area shown. 2013 Michael Swanbom BY NC SA a k d → Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 4 mm b 22 mm 5 mm d 9 mm h 26 mm w 3 mm The a coordinate of the centroid is ā = mm. The y coordinate of the centroid is j mm.ZV. p 9:-9 A docs.google.com * Asiacell liı. The force F= 450 lb acts on the frame. Resolve this Iorce into components acting along members AB and AC, and determine the magnitude of each component. 30 45 450 lb إضافة ملفThe figure below shows a steel structure made up of two pre-assembled segments that are hoisted by a mobile crane using a bespoke lifting frame. Each cable must withstand loads of FAB = FAC = FAD = FAE = 4000 kN. You must provide an accurate answer in scientific standard form with one decimal place only. In cartesian vector and in scalar form, compute the rAB, rAC, TAD & rAE length. 14 m 6m 6 m в 3 m 3 m X
- S00 Ib In the fig. shown, compute the ff: (16-18) the resultant using cosine law (force polygon) 60 R = 35 (19-20) the angle of the R measured 500 lb cW from the x- axis.Compute the coordinates of the centroid (, y) of the area shown. Also compute the area moment of intertia about the x' axis that passes through the centroid. 2013 Michael Swanbom BY NC SA d C Ka*b*c Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value а 33 mm 19 mm 17 mm d 68 mm The x coordinate of the centroid is a = mm. The y coordinate of the centroid is y mm. The moment of inertia about the x' axis going through the centroid is Iæ' mm4.Compute the coordinates of the centroid (î, g) of the area shown. Also compute the area moment of intertia about the r' and y' axes with origin at the centroid. 2013 Michael Swanbom cc BY NC SA a k-d Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 14 mm 111 mm 12 mm d 45 mm h 89 mm w 22 mm The z coordinate of the centroid is a = mm. The y coordinate of the centroid is j mm. The moment of inertia about the z' axis going through the centroid is Iz mm. The moment of inertia about the y' axis going through the centroid is Iy = mm*.