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- two ammeters also of negligible resistance, three resistors and two high resistance The circult dłagram shows a circuit consisting of a battery of negligible resistance, voltmeters. The reading on A, is 1A. V, 60 A1 V2 12 0 3.1 Define the term electric current. 3.2 Complete the following sentence by filling in the missing words. Resistors in series divide (3.2.1)....and resistors In parallel divide (3.2.2) ... 3.3 Calculate the: 3.3.1 Effective resistance of the parallel combination of resistors. 3.3.2 Total resistance of the circuit. 3.3.3 Reading on ammeter A2. 3.3.4 Reading on voltmeter V1 3.4 If the 6 2 resistor "burns out" will the total resistance of the circult INCRE DECREASE or REMAIN THE SAME? USIThe resistance of gold wire used in circuits is usually negligible compared to the components in the circuit, and can be ignored. For long, thin wires, this is no longer true. Calculate the resistance, in ohms, of a length of gold wire, 46.6 cm long, with a cross sectional area of 2.5 mm2. The resistivity of gold is 2.35×10-8 Ω.m. Use 2 significant figures in your answer.In the circuit shown below, Vs = 60 V, R1 = 7 Q, R2 =10 V, R3 = 6 Q and R4 = 6 Q. The Thevenin equivalent of this circuit consists of a voltage source Vth and series resistance RTh. FInd Vth and Rth and hence determine the current that will flow through a 50 Q resistor connected between points A and B. Give your answer in Amps to three decimal places. RTh I R3 R2 TA Vs VTh B Next > < Previous R4 R1 That -A B
- Find the expression for the equivalent resistance of 3 resistors (R1,R2,R3) connected in parallel. Sol. In a parallel connection, voltage drops across the resistors so: |= |1+ Using, Ohm's Law V = | we derive, that 1 = V1/ 12 = V2/ 13=V3/ Since, the voltage is the same on all resistors, then V = V1 = Substituting to the, first equation above, we get the following | = V1/ + V2/ + V3/ So: 1 1 + R1 1 1 Rea R2 R3Suppose a 6-V battery has an internal resistance of 0.4 ohm. Overall Hint a. What is the current that flows through the battery, if the battery terminals are momentarily shorted together? Hint for (a) Current of A flows through the battery. b. What is the terminal voltage if the battery delivers 0.45 amps to a circuit? Hint for (b) The terminal voltage is V.Consider the circuit shown in the diagram below. The battery has a voltage V = 12.0 V and the resistors have the following values. R, = 1.40 N; R, = 2.80 N; R, = 7.00 N; R, = 4.20 N How much current flows through each of the four resistors? 5.71 I, = What is the total current delivered by the battery? What is the voltage across R,? What are the voltages across each of the three parallel resistors? A I2 = I, = A I = A R2 R1 ww ww ww
- Question 4: This question is a "theoretical game." Don't actually try to find resistors in the stock room to solve this question. Suppose you have only two boxes of resistors available to you. One box is filled with 10002 resistors, and the other box is filled with 6002 resistors. However, you need a 1300N resistance. How could you use these resistors to produce the desired 13002 resistance? Show how (draw a circuit diagram of the resistors – similar to Figure 1 and 2) you would connect/combine the necessary resistors together, and include the theoretical calculations that verify that this combination indeed results in a 13002 resistance. esistoA 35 Ohms, 55 Ohms, and 85 Ohms resistors are connected in parallel. The resistors are then connected to a 35-V battery. 1. The equivalent (total) resistance of the circuit is Ohms. Round the final answer to a whole number. 2. The current through 85 Ohms resistor is A. Round the final answer to 1 decimal place. 3. W is dissipated in the 85 Ohms resistor. Answer in a whole number.Find the current I through the circuit.I= (mA). Find the voltage across each resistor. Give your answer as a comma-separated list in unit of volt, as an absolute value. potential drops across R1, R2, R3, R4, and R5 (in volt, in order): What is the power supplied by the batteries—that is, the power dissipated or consumed by the circuit?P= (W).
- Consider a simple circuit consisting of a battery, a closed switch, and a resistor. The voltage across the battery is 1.72 V, and the current through the resistor is 3.93 A. If the resistor is a cylindrical resistor of length 0.06 m made of a material with resistivity of 5.6x10-6 ohm-meters, what is the cross-sectional area of the resistor element? Your answer should be in m2.Consider the circuit shown in the figure below. (Let R1 = 5.00 Ω, R2 = 7.00 Ω, and E = 10.0 V.). . (a) Find the voltage (in V) across R1.. . . . . (b) Find the current (in A) in R1.What is the equivalent resistor between the terminals a and b if you replace R1 by 20 Ohm and R2 by 40 Ohm ? This combination of resistors goes to infinity by repeating itself. Write your answer in units of Ohm. No decimal points is necessary. Maximum od 4% of error is accepted in your answer. R1 R, R2 R2 b. R1 R,