Maximize Z-$46X1 + $69X2 Subject to: 4X1+6X2 ≤ 84 (Time in department 1) 2X1+1 X2 2 20 (Time in Department 2) 4X1 s 60 (Time in Department 3) Using graphical procedure, solve the problem. (Graph the constraints and identify the region of feasible solutions). What are the values of X1, X2 the three slacks S1, S2, S3, and the value of the objective function (Z) at optimum? If there are multiple optimum solutions, please give two of the optimum solutions.

Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter5: Network Models
Section5.5: Shortest Path Models
Problem 32P
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Problem 1. You are given the following linear programming problem regarding production of two products X1 and X2.
Maximize Z= $46X1 + $69X2
Subject to:
4X1+ 6X2 ≤ 84 (Time in department 1)
2X1+1 X2 2 20 (Time in Department 2)
4X1
≤ 60 (Time in Department 3)
Using graphical procedure, solve the problem. (Graph the constraints and identify the region of feasible
solutions). What are the values of X1, X2 the three slacks S1, S2, S3, and the value of the objective function
(Z) at optimum? If there are multiple optimum solutions, please give two of the optimum solutions.
YOUR ANSWERS:
O Optimum solution 1:
1 X1-
X2=
$1=
S2 =
5
S SHOW YOUR GRAPH BELOW:
S3=
Z=
2
3 Optimum solution 2: (if there is a second optimum solution)
X1 =
X2 =
$1=
S2=
S3-
Z-
Transcribed Image Text:Problem 1. You are given the following linear programming problem regarding production of two products X1 and X2. Maximize Z= $46X1 + $69X2 Subject to: 4X1+ 6X2 ≤ 84 (Time in department 1) 2X1+1 X2 2 20 (Time in Department 2) 4X1 ≤ 60 (Time in Department 3) Using graphical procedure, solve the problem. (Graph the constraints and identify the region of feasible solutions). What are the values of X1, X2 the three slacks S1, S2, S3, and the value of the objective function (Z) at optimum? If there are multiple optimum solutions, please give two of the optimum solutions. YOUR ANSWERS: O Optimum solution 1: 1 X1- X2= $1= S2 = 5 S SHOW YOUR GRAPH BELOW: S3= Z= 2 3 Optimum solution 2: (if there is a second optimum solution) X1 = X2 = $1= S2= S3- Z-
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