mechanism 1 overall reaction is 2NO + Cl2 --> 2NOCl NO + Cl2 = NOCl2 fast equilibrium NOCl2 + NO---> 2NOCl slow rate law for mechanism 1 is rate=k[no2]^2[cl2] mechanism 2 Cl2 --> 2Cl slow Cl + NO --> NOCl fast rate law for this mechansim 2 is rate=k[cl2] i noticed that when the mechanism has a fast reaction at equilibrium, the rate law includes reactants form both fast and slow, whereas when the reaction has fast reactions not at equilibrium, the rate law is only the reactants from the slow step (rate determining step) why is the rate law different when the fast reaction is at equilibrium vs when the mechansim has a fast reaction not at equilibrium?
mechanism 1 overall reaction is 2NO + Cl2 --> 2NOCl NO + Cl2 = NOCl2 fast equilibrium NOCl2 + NO---> 2NOCl slow rate law for mechanism 1 is rate=k[no2]^2[cl2] mechanism 2 Cl2 --> 2Cl slow Cl + NO --> NOCl fast rate law for this mechansim 2 is rate=k[cl2] i noticed that when the mechanism has a fast reaction at equilibrium, the rate law includes reactants form both fast and slow, whereas when the reaction has fast reactions not at equilibrium, the rate law is only the reactants from the slow step (rate determining step) why is the rate law different when the fast reaction is at equilibrium vs when the mechansim has a fast reaction not at equilibrium?
Chapter12: Chemical Kinetics
Section: Chapter Questions
Problem 75AE: One mechanism for the destruction of ozone in the upper atmosphere is a. Which species is a...
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mechanism 1
overall reaction is 2NO + Cl2 --> 2NOCl
NO + Cl2 = NOCl2 fast equilibrium
NOCl2 + NO---> 2NOCl slow
rate law for mechanism 1 is rate=k[no2]^2[cl2]
mechanism 2
Cl2 --> 2Cl slow
Cl + NO --> NOCl fast
rate law for this mechansim 2 is rate=k[cl2]
i noticed that when the mechanism has a fast reaction at equilibrium, the rate law includes reactants form both fast and slow, whereas when the reaction has fast reactions not at equilibrium, the rate law is only the reactants from the slow step (rate determining step)
why is the rate law different when the fast reaction is at equilibrium vs when the mechansim has a fast reaction not at equilibrium?
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