Molecular Shape of OF2 (1) Oxygen (2) Fluorine 2 буудл A₁ B₂ E₂ = ABE₂ Step 1: Find the Central Atom Central atom is: Look your line bond structure on page 1. Step 3: Choose the ABE classification Circle the correct AB,E, notation. Recall, we use (A) to represent the central atom, (B) to represent the number of atoms bonded to the central atom, and (E) to represent the number of lone pairs AB1E3 AB₁E2 AB₁E AB₂E AB₂E2 AB2 AB₂E AB3 Step 5: Use the Molecular Shape table from your notes to draw the ball and stick representation AB4 (F) Central atom A Batom surrounding central atom) lone pair E lonc pair central atoml Step 2: Count number of atoms bonded to the central atom (B) # of atoms bonded to central atom= B = Count number of lone pairs on the central atom (E) # of lone pairs on central atom=E=_ Step 4: Use the Molecular Shape Table from your notes to select the molecular shape and bond angles. Molecular Shape= Bond angles. Bent ~110° Step 6: Determine Polarity Is the central atom surrounded by identical electron groups? Circle one yes no If the answer was yes, then the molecule is nonpolar. If the answer is no, then the molecule is polar. Is the molecule polar? Symmetrical Circle one: (yes no لام 23 As-
Molecular Shape of OF2 (1) Oxygen (2) Fluorine 2 буудл A₁ B₂ E₂ = ABE₂ Step 1: Find the Central Atom Central atom is: Look your line bond structure on page 1. Step 3: Choose the ABE classification Circle the correct AB,E, notation. Recall, we use (A) to represent the central atom, (B) to represent the number of atoms bonded to the central atom, and (E) to represent the number of lone pairs AB1E3 AB₁E2 AB₁E AB₂E AB₂E2 AB2 AB₂E AB3 Step 5: Use the Molecular Shape table from your notes to draw the ball and stick representation AB4 (F) Central atom A Batom surrounding central atom) lone pair E lonc pair central atoml Step 2: Count number of atoms bonded to the central atom (B) # of atoms bonded to central atom= B = Count number of lone pairs on the central atom (E) # of lone pairs on central atom=E=_ Step 4: Use the Molecular Shape Table from your notes to select the molecular shape and bond angles. Molecular Shape= Bond angles. Bent ~110° Step 6: Determine Polarity Is the central atom surrounded by identical electron groups? Circle one yes no If the answer was yes, then the molecule is nonpolar. If the answer is no, then the molecule is polar. Is the molecule polar? Symmetrical Circle one: (yes no لام 23 As-
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter3: Atomic Shells And Classical Models Of Chemical Bonding
Section: Chapter Questions
Problem 99AP: A stable triatomic molecule can be formed that contains one atom each of nitrogen, sulfur, and...
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Question
I would like to you help me with my homework because I struggled with step 6. Can you help me with step 6, please?
Transcribed Image Text:Molecular Shape of OF2
(1) Oxygen
(2) Fluorine
2 вхудел
A₁ B₂ E₂ = ABE₂
Step 1: Find the Central Atom
Central atom is:_
Look your line bond structure on
page 1.
AB3E
¡F:
Step 3: Choose the ABE classification
Circle the correct AB E, notation.
Recall, we use (A) to represent the
central atom, (B) to represent the
number of atoms bonded to the central
atom, and (E) to represent the number
of lone pairs
AB₁E3 AB₁E2 AB₁E
AB₂E
AB₂E2
AB2
AB3 AB4
Step 5: Use the Molecular Shape
table from your notes to draw the
ball and stick representation
Central atom A
Blatom surrounding central atom
lone pair E lone pair central atoml
Step 2:
Count number of atoms bonded to the central
atom (B)
# of atoms bonded to central atom = B =
Count number of lone pairs on the
central atom (E)
# of lone pairs on central atom = E=_
2
Step 4: Use the Molecular Shape Table from
your notes to select the molecular shape and
bond angles.
Molecular Shape=
Bond angles =
Bent
~110°
Step 6: Determine Polarity
Is the central atom surrounded by identical
electron groups?
Circle one yes no
If the answer was yes, then the molecule is
nonpolar. If the answer is no, then the molecule
is polar.
Is the molecule polar? Symmetrical
Circle one: (yes
no
لام
Ox
23
が、
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