n the calorimetry experiment was used to measure the heat of reaction for an endothermic process, what would have been different about the observed change in temperature?

Chemistry for Engineering Students
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ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
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Chapter9: Energy And Chemistry
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* t dhe calorimetry experiment was used to measure the heat of reaction for an endothermic
process, what would have been different about the observed change in temperature?
2. When calculating the heat of reaction why did we have to add in C
AT?
calorimeter
3. Why were we able to assume that the C
solution
= C
water
4. The data collected today may have shown a decrease in temperature after several minutes
of constant temperature. What does the eventual decrease in temperature tell us about the
calorimeter?
5. In a calorimetry experiment similar to the one performed today, a student used 50.0 mL
of 1.0 M NaOH and 50.0 mL of 1.0 M HCl each initially at 22.5 °C. The maximum
temperature observed after mixing was 28.0 °C. What is the heat of reaction in units of kJ?
Show all work.
6. The true value for the experiment described in the previous question is 2.89 kJ. Calculate
the % error.
Transcribed Image Text:* t dhe calorimetry experiment was used to measure the heat of reaction for an endothermic process, what would have been different about the observed change in temperature? 2. When calculating the heat of reaction why did we have to add in C AT? calorimeter 3. Why were we able to assume that the C solution = C water 4. The data collected today may have shown a decrease in temperature after several minutes of constant temperature. What does the eventual decrease in temperature tell us about the calorimeter? 5. In a calorimetry experiment similar to the one performed today, a student used 50.0 mL of 1.0 M NaOH and 50.0 mL of 1.0 M HCl each initially at 22.5 °C. The maximum temperature observed after mixing was 28.0 °C. What is the heat of reaction in units of kJ? Show all work. 6. The true value for the experiment described in the previous question is 2.89 kJ. Calculate the % error.
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