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- Find the internal force systems acting on sections 1 and 2.The bent rod of negligible weight is supported by the ball-and-socket joint at B and the cables attached to points A and C. Find the forces in the cables and the magnitude of the reaction at B. Dimensions Figure P.5.39If F1 = 390 N force is applied to the piston with d1 = 4 cm diameter, what is the magnitude of the force F2 that can be resisted by the piston with d2 = 10 cm diameter? Neglect the weights of the pistons.
- Two masses are attached to a uniform meter stick as shown in the figure below. The masses of m1 and m2 are as given and the meter stick weighs 150 g. A force F with unknown magnitude is applied on one end of the stick at an angle of 30° to balance the system. 30 cm 40 cm 30 cm 30° m1 50 g m2 75 g slImstimee (a) What is the magnitude of F? (Ans: 6.21 N) (b) What are the reaction forces on the support? (Ans: Rx = 5.38 N; Ry = 5.80 N)The figure shows a mechanical model of the Russel fracture traction device and the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=200 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=10 cm . Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A ( 3L/4= 75 cm) . The angle that cable 2 makes with the horizontal is measured as β=40 ° . Accordingly, in order for the leg to remain in balance in the position shown; a) Find the tensile force T 1 in cable 1 . (Write your result in N ) b) Find the tensile force T 2 in cable 2 . (Write your result in N ) c) Find the angle α of cable 1 with the horizontalThe figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=250 N. The distance between the points A and B where the cables are attached to the leg is given as L=100 cm and the angle of the leg with the horizontal is γ=6°. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=40°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. Response
- The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The distance between the points A and B where the cables are attached to the leg is given as L=100 cm and the angle of the leg with the horizontal is given as γ=8°. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=50°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N)b) Find the tensile force T2 in cable 2. (Write your result in N)c) Find the angle α of cable 1 with the horizontal.The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. ResponseThe figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal.
- An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F,=200 Ibf, F2=250 lbf, and F3=100 lbf with 0 = 30 degrees and p=27.1 degrees. If the eye bolt is in equilibrium, what is the x-component of the sum of other forces (reaction force) on the bolt? If you add up the three force vectors, the reaction force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The x-direction is positive and to the right. Eye bolt rsteel plate Nut & WasherA 6-m long ladder has a mass of 10 kg, and its center of gravity is 2.4 m from the bottom along the ladder. The ladder is resting on a 5° upward sloping floor at A and on a wall inclined to the right at 5° from the vertical at B, so that it makes an angle of 60° with the horizontal. How far up along the ladder can a 78-kg man climb before the ladder is on the verge of slipping? The angle of friction at all contact surfaces is 15°. Also determine the total reaction at A and B in Newton. Note: Point A is at the left of point B. SOLVE ASAPA 6-m long ladder has a mass of 16 kg, and its center of gravity is 2.4 m from the bottom along the ladder. The ladder is resting on a 5° upward sloping floor at A and on a wall inclined to the right at 5° from the vertical at B, so that it makes an angle of 60° with the horizontal.How far up along the ladder can a 79-kg man climb before the ladder is on the verge of slipping? The angle of friction at all contact surfaces is 15°. Also determine the total reaction at A and B in Newton. Note: Point A is at the left of point B.