nductor with a radius (r) and a charge Q, depending upon the following cases: Calculate the electric field and electric potential at: d < r d > r

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PROBLEM:
Write a program that computes for the Electric Field and Electric Potential at a given point in a spherical conductor with a radius (r) and a charge Q, depending upon the following cases:

Calculate the electric field and electric potential at:

  1. d < r

  2. d > r

  3. d = r


SPECIFICATIONS:

- The program will depend on the input parameters to determine which case to use in computing for the electric field and electric potential at different points:

  • Point is inside the conductor (d < r)
  • Point is outside the conductor (d > r)
  • Point is on the surface of the conductor (d = r)

- The user will input the charge Q, the radius of the conductor (r) and the distance of the point from the center (d)

- The constant k = 9x10^9 = 9000000000

- The program will provide an output for the electric field (V/m) and for the electric potential (V)

- You may only use the codes that we studied in our lectures.

- All lines of codes should have a comment/pseudocode.

- Save your cpp file as  Surname - PE (Example: Pangaliman - PE.cpp)

 

To recall, the formula for solving the electric field and electric potential in electrostatic equilibrium is as follows:

A. Point is inside the conductor (r > d):
Electric Field = 0
Electric Potential = kQ/r


B. Point is outside the conductor (r < d):
Electric Field = kQ/d2
Electric Potential = kQ/d

C. Point is on the surface of the conductor (r = d)

Electric Field = kQ/r2
Electric Potential = kQ/r

TEST CASES:


If the r < d:

Enter charge (Q): 0.4

Enter the radius of the spherical conductor (r): 5

Enter the distance of the point from the center (d): 60


The electric field is 1000000 V/m and the electric potential is 60 000 000 V.


If the r > d:

Enter charge (Q): 20

Enter the radius of the spherical conductor (r): 500

Enter the distance of the point from the center (d): 60

The electric field is 0 V/m and the electric potential is 360 000 000 V.

C. Point is on the surface of the conductor (r = d)
Electric Field = kQ/r?
Electric Potential = kQ/r
TEST CASES:
If the r< d:
Enter charge (Q): 0.4
Enter the radius of the spherical conductor (r): 5
Enter the distance of the point from the center (d): 60
The electric field is 1000000 V/m and the electric potential is 60 000 000 V.
If the r> d:
Enter charge (Q): 20
Enter the radius of the spherical conductor (r): 500
Enter the distance of the point from the center (d): 60
The electric field is 0 V/m and the electric potential is 360 000 00 V.
Transcribed Image Text:C. Point is on the surface of the conductor (r = d) Electric Field = kQ/r? Electric Potential = kQ/r TEST CASES: If the r< d: Enter charge (Q): 0.4 Enter the radius of the spherical conductor (r): 5 Enter the distance of the point from the center (d): 60 The electric field is 1000000 V/m and the electric potential is 60 000 000 V. If the r> d: Enter charge (Q): 20 Enter the radius of the spherical conductor (r): 500 Enter the distance of the point from the center (d): 60 The electric field is 0 V/m and the electric potential is 360 000 00 V.
- The user will input the charge Q, the radius of the conductor (r) and the distance of the point from
the center (d)
- The constant k = 9x10^9 = 9000000000
- The program will provide an output for the electric field (V/m) and for the electric potential (V)
- You may only use the codes that we studied in our lectures.
- All lines of codes should have a comment/pseudocode.
- Save your cpp file as Surname - PE (Example: Pangaliman - PE.cpp)
To recall, the formula for solving the electric field and electric potential in electrostatic equilibrium is as
follows:
A. Point is inside the conductor (r > d):
Electric Field = 0
Electric Potential = kQ/r
B. Point is outside the conductor (r < d):
Electric Field = kQ/d2
Electric Potential = kQ/d
Transcribed Image Text:- The user will input the charge Q, the radius of the conductor (r) and the distance of the point from the center (d) - The constant k = 9x10^9 = 9000000000 - The program will provide an output for the electric field (V/m) and for the electric potential (V) - You may only use the codes that we studied in our lectures. - All lines of codes should have a comment/pseudocode. - Save your cpp file as Surname - PE (Example: Pangaliman - PE.cpp) To recall, the formula for solving the electric field and electric potential in electrostatic equilibrium is as follows: A. Point is inside the conductor (r > d): Electric Field = 0 Electric Potential = kQ/r B. Point is outside the conductor (r < d): Electric Field = kQ/d2 Electric Potential = kQ/d
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