NH4Cl + CaSO4 → (NH4)2SO4 + CaCl2 Δ Hf NH4Cl = -311.730 Δ Hf CaSO4 = -1434.5 kJ/mol Δ Hf (NH4)2SO4 = -1180,9 kJ/mol Δ Hf CaCl2 = -795.4 kJ/mol What us What is the ΔH°f of the the reactant? What us What is the ΔH°f of the the product? What is the ΔH°rxn of this given reaction? Round your answers in 2 decimal places no need to write the unit

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NH4Cl + CaSO4 →  (NH4)2SO+ CaCl2

Δ Hf NH4Cl = -311.730

Δ Hf  CaSO4 = -1434.5 kJ/mol

Δ Hf (NH4)2SO4 =  -1180,9 kJ/mol

Δ Hf CaCl2 = -795.4 kJ/mol

 

What us What is the ΔH°f of the the reactant? 

What us What is the ΔH°f of the the product? 

What is the ΔH°rxn of this given reaction? 

 

Round your answers in 2 decimal places no need to write the unit

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