O 9, 0 2k91 + b O O kq194 kq294 a+b + 2kq2 b + 94 + + 2kq3 b kq194 kq294 a+=b √b²+a² Okq194 kq294 kq394 + + √b²+a² a+b √b²+a² kq394 ¹b²+ a² √4 + + 2kq3 kq194 kq294 kq394 + + √b²+a² a+b √b²+a² a 193 circle + kq192 + kq293 √2 b 2 kq394 kq192 + b²+a² √2, 2 + √2b 2 + kq293 √2, 2 kq193 b + kq193 b

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Question
Canvas
← → X Ⓡ
9,
O
X
0 2k91 +
b
√4
984
kq194 kq294 kq394
a+b
¹b²+ a²
²+a²
+
kq194
kq294
+
√b²+a² a+b
kq 194
¹ b² + a²
kq194 kq294
√b² +a²
a+b
b
2kq2 2kq3
+
b
b
+
+
kq294
1
a+-b
2
+
a
+
+
+
+
2kq3
a
kq394
√√b²+a²
kq394
√b²+a²
аз
3
+
kq394
²b²+a²
circle
+
1
kq192 kq2q3 kq193
√2 b
b
√2b
2
2
+
kq192
√2b
-b
2
+
+
kq293
√2 b
2
+
kq193
b
4
Transcribed Image Text:Canvas ← → X Ⓡ 9, O X 0 2k91 + b √4 984 kq194 kq294 kq394 a+b ¹b²+ a² ²+a² + kq194 kq294 + √b²+a² a+b kq 194 ¹ b² + a² kq194 kq294 √b² +a² a+b b 2kq2 2kq3 + b b + + kq294 1 a+-b 2 + a + + + + 2kq3 a kq394 √√b²+a² kq394 √b²+a² аз 3 + kq394 ²b²+a² circle + 1 kq192 kq2q3 kq193 √2 b b √2b 2 2 + kq192 √2b -b 2 + + kq293 √2 b 2 + kq193 b 4
Canvas
→ XU
XO
What is the correct expression for the potential energy of the point charge distribution illustrated below. All charges are free to move.
حل
O2kq1
b
+
X
O kq194
√b² + a²
2
kq 194 kq294 kq394
+
√√2/20² + a² a+zb
√√²/b² + a²
2kq2
b
+
+
kq 194
+
√b² + a²
b
kq294
a+b
kq294
a+b
92
94
a
2kq3
b
+
+
+
+
2kq3
a
kq3q4
√b²+a²
kq3q4
√b² + a²
+
circle
аз
kq192
√2b
2
1
+
kq293 kq193
+
√2b
b
2
D
Transcribed Image Text:Canvas → XU XO What is the correct expression for the potential energy of the point charge distribution illustrated below. All charges are free to move. حل O2kq1 b + X O kq194 √b² + a² 2 kq 194 kq294 kq394 + √√2/20² + a² a+zb √√²/b² + a² 2kq2 b + + kq 194 + √b² + a² b kq294 a+b kq294 a+b 92 94 a 2kq3 b + + + + 2kq3 a kq3q4 √b²+a² kq3q4 √b² + a² + circle аз kq192 √2b 2 1 + kq293 kq193 + √2b b 2 D
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