O(g) +e-  O-(g) ∆Ho= -142 kJmol-1  O+2e-  O2-(g) ∆H o= + 712 kJ mol-1 Calculate ∆Ho for the reaction : O- + e-  O2- (g) .

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter16: Thermodynamics
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Problem 31E: A reaction has H298=100 kj/mol and S298=250 J/mol K. Is the reaction spontaneous at room...
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O(g) +e-  O-(g) ∆Ho= -142 kJmol-1 
O+2e-  O2-(g) ∆H
o= + 712 kJ mol-1
Calculate ∆Ho
for the reaction : O- + e-  O2-
(g) .

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