On a particle of mass m = 20gr, three forces F1, F2 and F3 act in the plane of the paper. The forces F2 = 4N, F3 = 3 N and F1 is unknown as indicated in the figure. If a product
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On a particle of mass m = 20gr, three forces F1, F2 and F3 act in the plane of the paper. The forces F2 = 4N, F3 = 3 N and F1 is unknown as indicated in the figure. If a product of the action of these three forces the particle acquires an acceleration a = 0.2m/s2 in the direction θ=20°, determine the direction and the magnitude of the force F1.
- The alpha angle of the direction of the force F3 is 300°
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- Determine the magnitude of the y-component of force Q (N) if P=108.8 N, Q = 72.5 N , θ= 42.25° and α = 43.45°. Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of the y-component.Three force vectors act on a free body at the origin as shown. F1= 4 N F2=2.0 i + 3.1 J N F3= 6.3 N at 35° relative to positive x axis. a) Report the unit vector in the direction of F3 (in unit vector or i,j,k notation to 4 sig figs) b)Calculate the resultant force R, which is the sum of the three forces F1,F2, and F3 (in unit vector or i,j,k notation to 4 sig figs)The slope of the 7.9 kN force F is specified as shown in the figure. Express F as a vector in terms of the unit vectors i and j. Assume a = 11, b = 5. Answer: F = (i a b -x i+ MI j) kN
- A two dimensional force system is given. The objective is to find the resultant force of the system by using vector operations. There are three forces present in the system. A. Find the vector form for each of the three forces: F1=10, Theta 1=45: F2=40x Theta 2=135; F3=30, Theta 3=270 B.Find the vector form of the resultant force C.Find the magnitude of the resultant force D. Find the angle of the force referred from the x-axis and describe its directionF = (-30i + 60j + 60k )kN %3D Forces are concurrent at point O. Determine the magnitude of the resultant of the three vectors. a 71.5 kN b 187 kN F, = (60i – 20j+ 15k )kN c 116 kN d 83.7 kN Determine the angle between F, andF,. F, = (20j – 25k)kN X а 111° b 132° c 69.0° d 21.0° Select the expression that denotes a unit vector in the direction and sense of F,. a 0.625j -0.781k b 0.625i -0.781j c -0.625 j –0.781k d 0.625i +0.781jGiven the force F2 and the u and v axes. What are the magnitude (in Newton) of the component of this force along the u and v axes respectively.
- In the plane forces system, F1 = 3 kN, F2 = 6 kN and F3 = 10 kN. The direction of the force F3 is tan a = %, the moment arm of the force couple is di = 2 m and the action points of the forces are A2 (-2,5), A3 (-4,-4). Find the resultant force R as a vector and calculate the line of action. y F2 A2 H. F3 A3A block of mass m = 3.65 kg is pushed a distance d = 7.95 m along a frictionless horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle 0 = 39.0° below the horizontal as shown in the figure below. A block labeled m is on a horizontal surface. An arrow labeled vector F points downward and to the right at an angle e above the horizontal, and acts upon the upper left corner of the block. A faded image of the block is a distance d to the right of the block. (a) Determine the work done on the block by the applied force. (b) Determine the work done on the block by the normal force exerted by the table. (c) Determine the work done on the block by the force of gravity. (d) Determine the work done by the net force on the block.A chandelier hangs h = 0.74 m down from two chains of equal length. The chains are separated from one another by a length L = 0.85 m at the ceiling. The chandelier has a mass of m = 28 kg. What is the angle, θ in degrees, between one of the chains and the vertical where it contacts the chandelier?
- A block of mass m = 2.50 kg is pushed d = 3.00 m along a frictionless horizontal table by a constant applied force of magnitude F = 18.0 N directed at an angle θ = 25.0° below the horizontal as shown in the figure below. A block labeled m is on a horizontal surface. An arrow labeled vector F points downward and to the right at an angle θ above the horizontal, and acts upon the upper left corner of the block. A faded image of the block is a distance d to the right of the block. (a) Determine the work done by the applied force. (b) Determine the work done by the normal force exerted by the table. (c) Determine the work done by the force of gravity. (d) Determine the work done by the net force on the block.A block of mass m = 2.50 kg is pushed d = 2.90 m along a frictionless horizontal table by a constant applied force of magnitude F = 15.0 N directed at an angle θ = 25.0° below the horizontal as shown in the figure below. A block labeled m is on a horizontal surface. An arrow labeled vector F points downward and to the right at an angle θ above the horizontal, and acts upon the upper left corner of the block. A faded image of the block is a distance d to the right of the block. (a) Determine the work done by the applied force. J(b) Determine the work done by the normal force exerted by the table. J(c) Determine the work done by the force of gravity. J(d) Determine the work done by the net force on the block. Jment Chapter 05, Problem 007 There are two forces on the 1.82 kg box in the overhead view of the figure but only one is shown. For F, = 20.0 N, a = 13.5 m/s², and 0 = 21.5°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.) (a) Number i + jUnits (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work SUBMIT ANSWER SAVE FOR LATER Question Attempts: 0 of 10 used