| (56- x-x2) dx has its largest Find two numbers a and b with asb such that value. a a = and b =

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Q: (c) Can you explain how to compute , 1(3f(x)g(x)) dx using the information given? Why or why not?

A: The given part is  ∫211fxdx=4.5∫211gxdx=13f and g are positive on [0,15] To compute: (c) ∫2113fxgxdx

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A: Our guidelines we are supposed to answer only one question. Kindly repost other question as the next…

Q: has its largest value. a = Find two numbers a and b with a ≤ b such that b = # (10 + 3x - x²) ¹/³ dx

A: We need to determine: a, b such that ∫ab10+3x-x213dx is maximum.  Here, a≤b.

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A: Here we have to evaluate I=∫-226x9-x5+14-x2dx

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A: This is based on the definite integral.

Q: %3D 3. If GH = 7x + 18 and JK = 81, find x. H G 丰 K 廿 世

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Q: 8x? -x t 8 x (x² + 4) 9. b.4mx4 3m (x+4-ラ4an)tc c. qlnxf 6m (x"+4)-Arctan )t c d. 2mxt 6m Ge?+4) -…

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Q: 9. -x² dx Choose the correct graph below. O A. O B.

A: Topic:- application of integration and geometry

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A: Given integral to evaluate ∫-227xe6xdx This can be integrated using the rule ∫u·vdx=u∫vdx-∫u'∫vdxdx

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Q: 8x3 dx The J using the substitution u = 5 – x* is ..

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Q: x2-4 dx%3D -3 Select one: a. 23 3 b. 28 3 C. 23

A: The only zero of x2-4 in the integration domain is x=-2.

Q: A = {-();n e N} -1 S = {x €R; 12x+ 1| < 5} -Y

A: Find the attachment

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Q: d2y at the point (2,) 48. Given yax-i.find -1, find - at the point|2, ах x

A: Given:The function y2x2 = 1.The point (2,1/2).

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A: Given function is fx=ln3x6+5x3+67      =ln3x6+5x3+617=17ln3x6+5x3+6

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Q: Q5) Solve the following using Trapezoidal rule with n6 f(x) = f*xinx. dx

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Q: Determine the value of k if |I +k dx = 2.

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Q: R- exp(A) E [g (X) | {X> 3}] ca

A: The value of gx=x2+1. For X~expλ, fxx&gt;3=fxPX&gt;3=λe-λx∫3∞λe-λxdx=λe-λxe-3λ. To determine the…

Q: 1. メt y+1 Find all

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Q: 2x dx Using an appropriate substitution, evaluate: A 4 C D D 4/2

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Q: df Calculate if f(u) = 6u², u(2) = −5, and u' (2) = −5. dx x=2 (Give your answer as a whole or exact…

A: We have to solve given Questions.

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Q: 2x1 Find the value of T such that P(Y > T) = 0.005, for Y = X3

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