Oxalic acid ionizes in two stages in aqueous solution: H2C2O4(aq) + H2O(€ )2H;0* (aq) + HC2O4 (aq) Kal = 5.9 × 10² HC,O, (aq) + H,O(e)2H;0*(aq) + C20?¯(aq) K22 = 6.4 × 10-5 Calculate the equilibrium concentrations of C¿O²¯, HC,O, H,C,O4, and OH- in a 0.10 M solution of sodium oxalate (Na,C¿O4).

Oxalic acid ionizes in two stages in aqueous solution: H2C2O4(aq) + H2O(€ )2H;0* (aq) + HC2O4 (aq) Kal = 5.9 × 10² HC,O, (aq) + H,O(e)2H;0*(aq) + C20?¯(aq) K22 = 6.4 × 10-5 Calculate the equilibrium concentrations of C¿O²¯, HC,O, H,C,O4, and OH- in a 0.10 M solution of sodium oxalate (Na,C¿O4).

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases

Section16.7: Calculations With Equilibrium Constants

Problem 16.5CYU: What are the equilibrium concentrations of acetic acid, the acetate ion, and H3O+ for a 0.10 M...

See similar textbooks

Similar questions

What are the equilibrium concentrations of acetic acid, the acetate ion, and H3O+ for a 0.10 M solution of acetic acid (K2 = 1.8 105)? What is the pH of the solution?
What are the products of each of the following acid-base reactions? Indicate the acid and its conjugate base and the base and its conjugate acid. HC1O4+ H2O — NH/ + H2O -» HCOr + OH" —
The pigment cyanidin aglycone is one of the anthocyanin molecules that gives red cabbage (Brassica oleracea var. capitata f. rubra) its characteristic red coloration. Many chemistry students have used this red cabbage indicator to study acid-base chemistry. Estimate tire pH range at which cyanidin agly-cone shows a color change. Anth-H(aq) Anth(aq) + H+ (aq) Ka = 1.3 107
What are the products of each of the following acid-base reactions? Indicate the acid and its conjugate base and the base and its conjugate acid. (a) HCIO4 + H2O (b) NH4 ++ H2O (c) HCO3 + OH
Which of the following compounds or ion has the strongest conjugate acid? Briefly explain your choice. (a) CN (b) NH3 (c) SO42
For conjugate acidbase pairs, how are Ka and Kb related? Consider the reaction of acetic acid in water CH3CO2H(aq)+H2O(l)CH3CO2(aq)+H3O+(aq) where Ka = 1.8 105 a. Which two bases are competing for the proton? b. Which is the stronger base? c. In light of your answer to part b. why do we classify the acetate ion (CH3CO2) as a weak base? Use an appropriate reaction to justify your answer. In general, as base strength increases, conjugate acid strength decreases. Explain why the conjugate acid of the weak base NH3 is a weak acid. To summarize, the conjugate base of a weak acid is a weak base and the conjugate acid of a weak base is a weak acid (weak gives you weak). Assuming Ka for a monoprotic strong acid is 1 106, calculate Kb for the conjugate base of this strong acid. Why do conjugate bases of strong acids have no basic properties in water? List the conjugate bases of the six common strong acids. To tie it all together, some instructors have students think of Li+, K+, Rb+, Cs+, Ca2+, Sr2+, and Ba2+ as the conjugate acids of the strong bases LiOH, KOH. RbOH, CsOH, Ca(OH)2, Sr(OH)2, and Ba(OH)2. Although not technically correct, the conjugate acid strength of these cations is similar to the conjugate base strength of the strong acids. That is, these cations have no acidic properties in water; similarly, the conjugate bases of strong acids have no basic properties (strong gives you worthless). Fill in the blanks with the correct response. The conjugate base of a weak acid is a_____base. The conjugate acid of a weak base is a_____acid. The conjugate base of a strong acid is a_____base. The conjugate acid of a strong base is a_____ acid. (Hint: Weak gives you weak and strong gives you worthless.)
Complete the balanced chemical equation for the following reaction between a weak acid and a strong base. H₂S (aq) + KOH(aq) → 2- 3C₂² 1 2 + (s) S 3 K Reset 4 (1) 5 6 LO O 7 (g) ㅈ H 8 9 11 (aq) Submit X 0 • x H₂O
The balanced molecular equation for complete neutralization of H2SO4 by KOH in aqueous solution is: Group of answer choices 2H+ (aq) + 2OH- (aq) → 2H2O (l) H2SO4 (aq) + 2KOH (aq) → 2H2O (l) + K2SO4 (aq) H2SO4 (aq) + 2OH- (aq) → 2H2O (l) + SO42- (aq) H2SO4 (aq) + 2KOH (aq) → 2H2O (l) + K2SO4 (s) 2H+ (aq) + 2KOH (aq) → 2H2O (l) + 2K+ (aq)
Complete the balanced molecular reaction for the following weak base with a strong acid: 2 NaCIO(aq) + H₂SO4 (aq) → 2 HCIO₂ + Na₂SO4 1 1 + Reset 4- 2 OH H 0₂ N U 3- 3 ☐3 ) ~ 4 4 H₂O H3O+ LO 5 05 14 ☐ 6 0 CO 02+ 7 07 CI U (s) (1) Na 3+ □ 8 9 4+ • x H₂O 0 09 口。 (g) (aq) S Delete
Calculate the pH and the pOH of these solutions: (c) 0.957 M HC2H3O2 (Ka = 1.8 x 10-5) pH = pOH =
Calculate pH and pOH for each of the following solutions and determine whether thesolution is acidic, basic or neutral:(i) [H3O+] = 4.1 x 10-10 M (ii) [OH–] = 7.6 x 10-3 M(iii) [OH–] = 6.9 x 10-4 M (iv) [H3O+] = 3.5 x 10-6 M
Kc for formic acid dissociation in water is 1.8x10-4. What are the equilibrium concentrations of H30+ HCOO- and HCOOH if the initial concentration of HCOOH is .15 mol? HCOOH (aq) +H20 (L) >< H30 (aq) + HCOO (aq)