parallel programmingWhat is the output of the code. Explain your answer 2.3.45.6.6847(def account1(atom 0(def account2 (atom 0: validator # (>= % 0))): validator # (>= % 0) ) )(defn transfer [from-acct to-acct amt](swap! to-acct + amt)(swap! from-acct amt))8. (future (transfer account1 account2 100))9.10.(println (str "account1: @account1))11. (println (str "account2: "@account2))12.TT

Name: parallel programmingWhat is the output of the code. Explain your answe
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Description: parallel programmingWhat is the output of the code. Explain your answer 2.3.45.6.6847(def account1(atom 0(def account2 (atom 0: validator # (>= % 0))): validator # (>= % 0) ) )(defn transfer [from-acct to-acct amt](swap! to-acct + amt)(swap! from-acc

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parallel programming What is the output of the code. Explain your answer

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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2.2.14 Sorted queues being combined. Create a static function that receives two queues of sorted items as inputs and returns a queue formed by combining the two queues into a single sorted order queue. 2.2.15 Bottom-up mergesort of a queue. Create an implementation of the bottom-up mergesort using the following strategy: Make N queues, each holding one of the N things, given N items. assemble the N queues into a queue. Apply Exercise 2.2.14's merging process to the first two queues several times, and at the conclusion, reinsert the combined queue.Continue until there is just one queue left in the queue of queues.
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d(i) State the main reason of using static access modifier.
In [13]: def isAbundant (x): ***Returns whether or not the given number x is abundant. A number is considered to be abundant if the sum of its factors (aside from the number) is greater than the number itself. Example: 12 is abundant since 1+2+3+4+6-16 > 12. However, a number like 15, where the sum of the factors. is 1 + 3 + 5 - 9 is not abundant. your code here sum-1 for i in range(2,x) if(x1==0): Bum-Bum+1 if(sum>) 1 print(x, 'is Abundant Number") else: print (x, 'is not Abundant Number') File "", line 19 else: SyntaxError: invalid syntax In [14]: abundant_numbers [12, 18, 20, 24, 30, 36, 40, 42, 48, 54, 56, 60, 66, 70, 72, 78, 80, 84, 88, 90, 96, 100, 102, 104, 108, 112, 114, 1201 for i in abundant numbers assert true (isAbundant (i), str(i) is abundant") not abundant_numbers [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23, 25, 26, 27, 28, 29, 91, 92, 93, 94, 95, 1191 for i in not abundant_numbers: assert true (not (isAbundant (i)), str(i) is not abundant")…