Part aWithout using exel PART A.) Decide which of the following machines should be selected (if one of them MUST beselected) using a Present Worth Analysis assuming 8% interest. I want to see PWp and PWQcalculated as part of the decision.PFirst Cost, $Annual Operating Cost,$/yearSalvage Value, $Life, years20,0004,00015,0005,0005,0005,0002PART B.) Decide which of the following alternatives should be selected (if one of them MUSTbe selected) using an Annual Worth Analysis assuming 12% interest. I want to see AWA andAWB calculated as part of the decision.AВFirst Cost, $Annual Operating Cost,$/yearSalvage Value, $Life, years50,00010,00090,0004,00013,00015,0003

The present value of a project is used to find its profitability by discounting cash flows and them…

PART A.) Decide which of the following machines should be selected (if one of them MUST be selected) using a Present Worth Analysis assuming 8% interest. I want to see PWp and PWQ calculated as part of the decision. P First Cost, $ Annual Operating Cost, $/year Salvage Value, $ Life, years 20,000 4,000 15,000 5,000 5,000 5,000 2

PART A.) Decide which of the following machines should be selected (if one of them MUST be selected) using a Present Worth Analysis assuming 8% interest. I want to see PWp and PWQ calculated as part of the decision. P First Cost, $ Annual Operating Cost, $/year Salvage Value, $ Life, years 20,000 4,000 15,000 5,000 5,000 5,000 2

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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2. It is rëquired to select one of the three machines. Which machine should be selected, based on the present worth comparison at an interest rate of 12% per year, if the costs are shown below? Туре X 7,650 1,200 Туре Y 12,900 900 2,000 Туре Z 17,000 750 First cost, $ Maintenance cost,.( $ lyear) Salvage value, ( $) Economic (years) 4,000 12 4
Using the following two relationships: AW = CR + A of AOC CR = -P(A/P,i,n) + S(A/F,i,n) %3D Calculate the Annual Worth (AW) based on the data for the following project: Corporate MARR = 10% Initial Investment Cost $1,000,000 Anticipated Project Life = 10 years Salvage Value at the end of 10 years $100,000 Annual Cost of Operation %3D $50,000 10% Compound Interest Factors
The following two alternatives are given. Data A B. First Cost $8,200 $5,600 Annual Cost $1,000 $800 Annual Benefit $2,700 $2,100 Life, Years 7. Salvage Value $2,800 $1,000 Assume that MARR is 15%. Use the incremental rate of return analysis to determine which alternative (A or B) one should choose. Find the AIRR, or a range of AIRR. O 10% O 10-12% O 12-15% O > 15%
EconomicS 2. Referring to the given data in 6.7/317 at the end of Chapter 6 (Engineering Economy by Sullivan et al), select the best alternative using: (a) PW (b) AW © FW (d) IRR 6-7. Three mutually exclusive design alternatives are being considered. The estimated cash flows for each alternative are given next. The MARR is 20% per year. At the conclusion of the useful life, the investment will be sold. A в $28,000 $55,000 $40,000 Annual expenses $15,000 $13,000 $22,000 Annual revenues $23,000 $28,000 $32,000 $6,000 $8,000 $10,000 Investment cost Market value Useful life 10 years 10 years 10 years 26.4% 24.7% 22.4% IRR A decision-maker can select one of these alternatives or decide to select none of them. Make a recommendation using the PW method. (6.4)
Q1- Consider the following two pumps at an interest rate of 15%. Use interest rate table method and spreadsheet method to determine which one should be installed based on present worth analysis? Brass Titanium First cost, $ Annual 0&M costs $/year Salvage value, $ Life -7500 -7500 -450 -350 1000 2000 8.
A firm is trying to decide which of two machines to purchase as described in in the table below. Using the interest rate 9% or 0.09, use present worth analysis to determine which machine, if either, should be purchased. Show all your work. Machine: A - B First Cost: $800 - $600 Annual Net Benefit: $130 - $230 Salvage Value: $40 - $20 Usefil Life (years): 9 - 3
Question 3. Choose the best piping systems as shown in the table below using Annual Worth method (MARR: 6%). Concrete piping UPVC piping Initial cost (OR) Ca Initial cost (OR) Annual 0&M (OR/y)" 10000 Annual O&M (OR/yr) 5000 Rehabilitation cost at the 120000 5th year Useful life (years)¤ 10 Useful life (years)= 20 Ca 1720102 1136000 1828000:
Q which project will be the best using (EAW). S Using the Benefit-Cost Ratio Method, Find what is the best alternative from the projects listed below if u know that (-10%) for both project. Details Initial investment (CU) Annual revenue (CU/year) Annual expense (CU/year) Project life (year) Investment due to replacement of some machines every 3 years. Salvage value (CU) Purchasing a new machine in the seventh year. 0 -113 000 Alternative 1 300 000 50 000 15 500 1 30 000 5 13 500 Q5:A person is planning a new business, the initial investment and cash flow pattern for a new business are shown below: Non Non 2 Year Cash flow (CU) The expected life of the project is five year.Find the rate of return for a new business. 30 000 3 30 000 Alternative 2 200 000 75 000 29 000 10 Non 4 30 000 22 000 13 000 5 30 000
1. Determine the B/C ratio for the following project. First Cost P100, 000 Project life, years 5 Salvage value P10, 000 Annual benefits P60, 000 Annual O and M P22, 000 Interest rate, % 15 Ans: B/C = 1.16
Given the financial data for four mutually exclusive alternatives in the table below, determine the best alternative using the incremental rate of return (AROR) analysis. MARR = 10%. A B C D $15,000 $21,200 $36,000 45,000 1,600 700 400 1,000 First cost O &M Cost/ year Benefit/year 8,000 9,000 13,000 Salvage value 3,000 4,600 6,000 Life in years 4 15,000 10,000
1. Data for two alternatives are given in the table below. Determine the X cost of alternative B so that the two alternatives will be equally desirable. Assume an interest of 11%. Use BCR analysis. ALTERNATIVE A Cost 9500 Salvage value 1000 1600 Annual benefit 2800 3700 Life (years) 12
Its required to select one of the two machines, if you know that the firms MARR-12% and if the costs are shown below: Project A Project B Initial cost, $ 7650 12900 Maintenance cost, S/year 1200 900 Salvage value, $ 2000 Economic life, year 4 Compare the two-alternative using: 1-Equavlent Annual worth comparison. 2- Present worth comparison

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