PART III: Post-lab Tasks 1) Disassmble the following code with gcc compiler using -Ol optimisation. Comment on the optimisation technique used by the compiler. int propagation() { int x,y,z, x=10; y=x+45; z-y+4; return z; Disassmble not assembly code If you provide assembly Code I will report

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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PART III: Post-lab Tasks
1) Disassmble the following code with gcc compiler using -Ol optimisation. Comment on the
optimisation technique used by the compiler.
int propagation()
{
int x,y,z,
x=10;
y=x+45;
z-y+4;
return z;
}
2) Disassmble the following code with gcc compiler using -O1 optimisation. Comment on the
optimisation technique used by the compiler.
#include <stdio.h>
int main()
{
int i, j;
for(i=0; i<10; i++)
{
Disassmble
not assembly code
If you provide assembly
Code I will report
}
j=i*7;
printf("i=%d, j =%d\n", i, j);
Transcribed Image Text:PART III: Post-lab Tasks 1) Disassmble the following code with gcc compiler using -Ol optimisation. Comment on the optimisation technique used by the compiler. int propagation() { int x,y,z, x=10; y=x+45; z-y+4; return z; } 2) Disassmble the following code with gcc compiler using -O1 optimisation. Comment on the optimisation technique used by the compiler. #include <stdio.h> int main() { int i, j; for(i=0; i<10; i++) { Disassmble not assembly code If you provide assembly Code I will report } j=i*7; printf("i=%d, j =%d\n", i, j);
3) Disassmble the following code with gcc compiler using O1 optimisation. Comment on the
optimisation technique used by the compiler. Write the equivalent optimised C function.
void set_row(double *a, double *b, int i, int n,int j)
for (i=0; i<n; i++)
for (j = 0; j<n; j++)
a[n*i+j] = b[j];
Transcribed Image Text:3) Disassmble the following code with gcc compiler using O1 optimisation. Comment on the optimisation technique used by the compiler. Write the equivalent optimised C function. void set_row(double *a, double *b, int i, int n,int j) for (i=0; i<n; i++) for (j = 0; j<n; j++) a[n*i+j] = b[j];
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