Perform the indicated operation using MATLAB syntax. Write the MATLAB syntax and output on the space provided. Include the screen shot of your MATLAB.
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LINEAR ALGEBRA - MATLAB ACTIVITY - Fundamentals of MATLAB
Perform the indicated operation using MATLAB syntax. Write the MATLAB syntax and output on the space
provided. Include the screen shot of your MATLAB.
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- int sum, k, i, j; int x[4] [4]={5,6,7,8},{1,2,3,4},{9,8,7,3},{2,1,7,1}; sum=0; for (i=1; i x[i-1][j] ) sum++; Give the value of sum after the statements are executed.A = {1,2,3} B = {1,2,3} C = {5,6,7} D = {0,1,2,3,4,5} Is A = C?int sum, k, i, j; int x[4][4] ={{5,1,7, 8},{1,4,3, 4},{9,6,7,3), (2,2,7,1}): sum-0; for(i=1; i x[i=1][j]) sumtt; Give the value of sum after the statements are executed.
- Solution Floating point representation: It is defined as the representation of floating numbers. It includes sign bit, exponent, and mantissa bits. Based on precision it has 2 types. 1. For IEEE 754 single-precision floating-point numbers, what is the exponent of a denormalized floating-point number in decimal? Solution: In IEEE 754 single-precision, exponent bits are 8. Therefore exponent = 2 ^(n-1) -1 = 2^(8-1) -1 = 127 OPTION D 2. For IEEE 754 single-precision floating-point numbers, how many bits for mantissa? Solution: In IEEE 754 single-precision, there are 23 bits for mantissa. sign = 1 bit exponent = 8 bits mantissa = 23 bits 3. For IEEE 754 single-precision floating-point numbers, which of the following is an example of NAN? Solution: In IEEE 754 single-precision, NAN is a special value where all exponents bits are 1's and the mantissa is non zero. a. 1 111 1 111 0000 0000 1101 0000 0000 0000 Exponent is not all 1's. Not a NAN b. 0 111 1 111 1000 0000…FI 2 Overview S To demonstrate you can implement the microservices architecture, write software comprised of three separate programs: W F2 7x 1. A program that generates pseudo-random numbers (PRNG Service) 2. A program that, given a non-negative integer i, returns the ith image in a set (order doesn't matter) (Image Service) If i is the number of images, modulo i by the size of the image set 3. A user interface (UI) that either has a button or can receive a user command. When the button is pushed or the command is entered... Programs can be written in any language(s). (a) UI calls the PRNG Service (b) UI calls the Image Service using the pseudo-random number from the PRNG Service (c) UI displays the image (or a path to it) Use any set of images (e.g., downloaded from https://www.kaggle.com/). Store images locally in a folder; no API calls needed. No DB needed. Requirements UI must either have a button (if UI is graphical) or be able to receive a user command (if UI is text-based) # 3…In questions 4-10 estimate the Big O value by analyzing the code. Note the algorithms are written in English. Hint: you are interested in the number of operations for each algorithm.
- Code this in C program A set of integers 0..MAX may be implemented using an array of boolean values. This particular implementation is called a bit-vector implementation of a Set. Since C doesn’t have the Boolean data type, then substitute TRUE with 1 and FALSE with 0, or define 1 and 0 as TRUE and FALSE, respectively.For example, if the integer 3 is an element of the set, then the array element indexed by 3 is TRUE. On the other hand, if 3 is not an element, then the array element indexed by 3 is FALSE. For example: if s = {3,4,6,8}, the array looks like this: 0 1 2 3 4 5 6 7 8 9 FALSE FALSE FALSE TRUE TRUE FALSE TRUE FALSE TRUE FALSE Implement a programmer-defined data type called BitSet to represent a set as follows:typedef int BitSet[MAX];Implement the following functions:void initialize(BitSet s); - set all array elements to FALSEvoid add(int elem,BitSet s);- set the item indexed by elem to TRUEvoid display(BitSet s);- display the set on the screen using set notation,…Please convert to C language //quadratic probing#include <bits/stdc++.h>using namespace std; void add_using_quadratic_probing(int hash[], int a){ //hash function h(x)=x%10 int k = a % 10; //quadratic probing int incr = 1; while (true) { if (hash[k] == -1) { hash[k] = a; break; } //quadratic increment of probe k = (k + int(pow(incr, 2))) % 10; incr++; }} int main(){ //set of input numbers vector<int> arr{ 123, 124, 333, 4679, 983 }; //initialize the hash table //each entry of the hash table is a single entry int hash[10]; //size of hashtable is 10 memset(hash, -1, sizeof(hash)); //initialize with empty initially for (int a : arr) { //hashing add_using_quadratic_probing(hash, a); } cout << "---------using quadratic probing---------\n"; cout << "Hash table is:\n"; for (int i = 0; i < 10; i++) { if (hash[i] == -1) cout…لتكن المصفوفة [x=[1,4,3,2;8,7,9,0;4,6,7,3 [Y=[1,6,7;5,6,4;7,8,9;0,3,4 [W=[1,3,4,5;7,6,8,9;0,9,1,2;4,5,2,3 اكتب كلا من الايعازات التالية : كون المصفوفة الفرعية من الصفوفةx حيث ان z= 6. 8 9. 9. 2.
- Especifique la longitud (número de elementos o tamaño del arreglo) de cada uno de los arreglos declarados a continuación: a) double A[5) = (-3.0, 9.44, 4.5); Longitud: !3! b) int M1[2][3] = {{2), {80, -10, 12) }; Longitud: c) char R[] = "S=Si o N=No"; Longitud:In C program A set of integers 0..MAX may be implemented using an array of boolean values. This particular implementation is called a bit-vector implementation of a Set. Since C doesn’t have the Boolean data type, then substitute TRUE with 1 and FALSE with 0, or define 1 and 0 as TRUE and FALSE, respectively. For example, if the integer 3 is an element of the set, then the array element indexed by 3 is TRUE. On the other hand, if 3 is not an element, then the array element indexed by 3 is FALSE. Implement a programmer-defined data type called BitSet to represent a set as follows: typedef int BitSet[MAX]; Implement the following functions: void initialize(BitSet s); - set all array elements to FALSE void add(int elem,BitSet s); - set the item indexed by elem to TRUE void display(BitSet s); - display the set on the screen using set notation, e.g. {3,4,5,6} - this means that you will print the index value if the content of that cell is TRUE void getUnion(BitSet result,BitSet s1,BitSet…Find error #include<bits/stdc++.h> using namespace std; class Solution{ public: bool isPossible(vector<int>ank,int n,int mid) { int count=0; for(int i=0;i<rank.size()) { int val= (-1 + sqrt(1+(8*mid)/rank[i]))/2; count+=val; } return count>=n; } int findMinTime(int N, vector<int>&A, int L){ int low=*min_element(A.end()),high=1000000; int ans=high; while(low<=high) { int mid=low+(high)/2; if(isPossible(A,mid)) { ans=mid; high=mid; } else low=mid; } return ans; } }; int main() { int t; cin>>t; while(t--) { int l; cin >> l; vector<int>arr(l); for(int i = 0; i < l; i++){ cin >> arr[i]; } Solution ob; int ans = ob.findMin(n, *arr, l); cout…