Phosphorus pentachloride decomposes according to the chemical equation PCl5(g)↽−−⇀PCl3(g)+Cl2(g) ?c=1.80 at 250  A 0.2738 mol sample of PCl5⁢(g) is injected into an empty 3.90 L reaction vessel held at 250⁢ ∘C.

Chemistry: Principles and Practice
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Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.86QE
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This is my second time asking this question, the first one came out as incorrect for both answers (I attached pictures of answers). I'm not sure what is done incorrectly.

 

Phosphorus pentachloride decomposes according to the chemical equation

PCl5(g)↽−−⇀PCl3(g)+Cl2(g) ?c=1.80 at 250 

A 0.2738 mol sample of PCl5⁢(g) is injected into an empty 3.90 L reaction vessel held at 250⁢ ∘C.

Calculate the concentrations of PCl5⁢(g) and PCl3(g) at equilibrium.

Phosphorus pentachloride decomposes according to the chemical equation
PCI, (g) = PCI, (g) + Cl, (g)
K. = 1.80 at 250 °C
A 0.2738 mol sample of PCl, (g) is injected into an empty 3.90 L reaction vessel held at 250 °C.
Calculate the concentrations of PCl, (g) and PCl, (g) at equilibrium.
0.00716
[PCI,] =|
M
Incorrect
0.00716
[PCI,] =
M
Incorrect
Transcribed Image Text:Phosphorus pentachloride decomposes according to the chemical equation PCI, (g) = PCI, (g) + Cl, (g) K. = 1.80 at 250 °C A 0.2738 mol sample of PCl, (g) is injected into an empty 3.90 L reaction vessel held at 250 °C. Calculate the concentrations of PCl, (g) and PCl, (g) at equilibrium. 0.00716 [PCI,] =| M Incorrect 0.00716 [PCI,] = M Incorrect
Let's put these values into the equilibrium constant formula:
[PCI,]
K.
[PC!3] [Clz]
= 1.80
0.070205 – x
= 1.80
х2
0.070205 – x = 1.80 x²
-
1.80 x? + x – 0.070205
By solving the above quadratic equation, we get:
x = 0.063049
Final answer
The equilibrium concentration of PCI5 is given by:
PCI5g = 0.070205 -XPC158 = 0.070205 -0.063049PC158 = 0.007156 MPCI5(g) = 0.00716 M
The equilibrium concentration of PCI3 is given by:
PC13g = XPC139 = 0.063049 MPCI3(g) = 0.0630 M
Transcribed Image Text:Let's put these values into the equilibrium constant formula: [PCI,] K. [PC!3] [Clz] = 1.80 0.070205 – x = 1.80 х2 0.070205 – x = 1.80 x² - 1.80 x? + x – 0.070205 By solving the above quadratic equation, we get: x = 0.063049 Final answer The equilibrium concentration of PCI5 is given by: PCI5g = 0.070205 -XPC158 = 0.070205 -0.063049PC158 = 0.007156 MPCI5(g) = 0.00716 M The equilibrium concentration of PCI3 is given by: PC13g = XPC139 = 0.063049 MPCI3(g) = 0.0630 M
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