In a setup like that in Figure 27.7, a wavelength of 625 nm is used in a Young's double-slit experiment. The separation between the slits is d = 1.4 x 10-5 m. The total width of the screen is 0.20 m. In one version of the setup, the separation between the double slit and the screen is LA = 0.29 m, whereas in another version it is LB = 0.37 m. On one side of the central bright fringe, how many bright fringes lie on the screen in the two versions of the setup? Do not include the central bright fringe in your counting. -m = 3 (Bright fringe) d m = 0 (Bright fringe) -m = 3 (Bright fringe) L. Figure 27.7 A: Number of bright fringes = Number i ! Units No units %3D B: Number of bright fringes = Number i Units No units

Principles of Physics: A Calculus-Based Text
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Chapter27: Wave Optics
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Problem 69P
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In a setup like that in Figure 27.7, a wavelength of 625 nm is used in a Young's double-slit experiment. The separation
between the slits is d = 1.4 x 10-5 m. The total width of the screen is 0.20 m. In one version of the setup, the separation
between the double slit and the screen is LA = 0.29 m, whereas in another version it is LB = 0.37 m. On one side of the
central bright fringe, how many bright fringes lie on the screen in the two versions of the setup? Do not include the
central bright fringe in your counting.
-m = 3 (Bright fringe)
d
m = 0 (Bright fringe)
-m = 3 (Bright fringe)
L.
Figure 27.7
A: Number of bright fringes = Number
i
!
Units
No units
%3D
B: Number of bright fringes = Number
i
Units
No units
Transcribed Image Text:In a setup like that in Figure 27.7, a wavelength of 625 nm is used in a Young's double-slit experiment. The separation between the slits is d = 1.4 x 10-5 m. The total width of the screen is 0.20 m. In one version of the setup, the separation between the double slit and the screen is LA = 0.29 m, whereas in another version it is LB = 0.37 m. On one side of the central bright fringe, how many bright fringes lie on the screen in the two versions of the setup? Do not include the central bright fringe in your counting. -m = 3 (Bright fringe) d m = 0 (Bright fringe) -m = 3 (Bright fringe) L. Figure 27.7 A: Number of bright fringes = Number i ! Units No units %3D B: Number of bright fringes = Number i Units No units
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