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- The following table gives the volume of nitrogen (reduced to 0°C and 1 bar) adsorbed per gram of active carbon at 0°C at a series of pressures: 1731 P/Pa v/(cm³ g-¹) 524 0.987 3.04 3058 C. 29 cc/g D. 23 cc/g E. None of the choices 5.08 4534 7.04 Determine the volume required to form a monolayer. A. 34 cc/g B. 40 cc/g 7497 10.31Adsorbates with a [1] desorption barrier desorb at [2] temperature 1 = high; 2 = low 1 = high; 2 = high47.The number of cm³ of methane, measured at STP, adsorbed on 1 g of charcoal at 0 °C and several different pressures is: P, cm Hg 10 20 30 40 cm³ adsorbed 9.55 14.51 19.2 20.4 Plot the data using the Freundlich isotherm and determine the constants k and $ expression y=k (concentrations)1/n in the Freundlich
- .. C Chrome File Edit View History Bookmarks OpenStax - Cher x app.101edu.co 1 7 +/- 2 5 Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene (C₂H₁) according to the following reaction: C₂H₁ (1) + O₂(g) + NH₂(g) → C₂H₂N₂(s) + H₂O(1) How many grams of water would be produced by the complete ammoxidation of 3.98 moles of o-xylene? 8 Chemistry 2e - CX . Question 13 of 24 | g 3 6 9 Profiles Tab Window Help O Aktiv Chemistry X X C + x 100 Submit : f Su C C Copp (CsH gram: of pht < Pre5g of a catalyst adsorbs 400cm3 of N2 at stp to form a monolayer. What is the. Surface area per Gram if the area occupied by a molecule of N2 is 16Akindly answer this problem and follow this format GIVEN REQUIRED SOLUTION and write regibly thank you so much For the adsorption of a substance A from aqueous solution by charcoal at25oC the freundlich constants are n=3.0 and k=0.50 for y in grams per gramand C in grams per liter. What weight of a W is adsorbed by 2 g of charcoalfrom 1 L of a solution containing originally 2 g of the substance?
- Calculate the isosteric enthalpy of adsorption from the following results which were obtained for the adsorption of 0.145 cm3, at STP, of nitrogen on charcoal: Temperature (K) Pressure (kPa) 195 156 244 380 273 567 Answer is [-7.53 kj/mol]FAlpOLSdkkCb8p7Lki9hSE-PEqyqO02a33Gom9YvugXuốb5uYkOPEUw/formResponse plify ern. Karely 1. Serena mixed two samples together: a gray solid that smells like flowers and a gray solid that smells like bleach. She analyzed the results and found two ending substances. One of the ending substances was a white solid. This ending substance is made up of the repeating group of atoms shown below. Which of the diagrams to the right shows the repeating groups of atoms that make up the samples Serena mixed together? Sample 1 Sample 2 An ending substance Sample 1 Sample 2 Properties: Bray solid mells like flowers Properties: gray solid smells like bleach Properties: white solid Sample 1 Sample 2 smells sour Sample Sample 1 Sample A. Diagram A B. Diagram B C. Diagram C O O OMoore 5e_C OWLV2 | Onli X Q ☆ * CE w.com/ilrn/takeAssignment/takeCovalentActivity... [Review Topics] [References] isms ots 2req Use the References to access important values if needed for this question. In a study of the conversion of methyl isonitrile to acetonitrile in the gas phase at 250 °C Visited 1 pts 2req CH3NC(g)- >CH3CN(g) 1 pts 2req the concentration of CH NC was followed as a function of time. It was found that a graph of In[CH3NC] versus time in seconds gave a 1 pts 2req straight line with a slope of -3.96x10-3 s and a y-intercept 52. 1 pts 2req Based on this plot, the reaction is v order in CH,NC and the rate constant for the reaction is 1 pts 2reg 1 pts 2reg 1 pts 2reg Submit Answer Retry Entire Group 9 more group attempts remaining Previous Next Email Instructor Save and Exit Cengage Learning | Cengage Technical Support 52% 1:41 PM 1/22/2021
- Calculate the amount of charcoal needed to adsorb 0.003g of Alizarin Yellow (M.W. = 287.23 g/mol), given that 1 g of charcoal has a surface area of absorption of 800 m², the contact area of 1 molecule of Alizarin Yellow is 200 Á² (1 Á = 1 × 10-10 m), and Avogadro's number is 6.02 x 1023 molecules/mol. 1.57 x 108 g 0.157 g 0.0157 g 0.00157 g22-30. (a) The mean free path is the average distance a molecule travels before colliding with another molecule. The mean free path, A, is given by A = kT/(V20P), where k is Boltzmann’s constant, T is temperature (K), P is pressure (Pa), and o is the collision cross section. For a molecule with a diameter d, the col- lision cross section is nd. The collision cross section is the area swept out by the molecule within which it will strike any other molecule it encounters. The magnetic sector mass spectrometer is maintained at a pressure of ~103 Pa so that ions do not collide with (and deflect) one another as they travel through the mass analyzer. What is the mean free path of a molecule with a diam- eter of 1 nm at 300 K in the mass analyzer?For N2 adsorbed on activated carbon at –77 °C, the following values of adsorbed gas (per gram of adsorbent) were obtained at different pressures: P/atm 3.5 10.0 16.7 25.7 33.5 39.2 v/(cm³/g) 101 136 153 162 165 166 - Estimate the volume value of the monolayer. - Calculate the coating fraction (θ) at a pressure of 10 atm. ANSWER: 0.82 - What would happen (increase / decrease) with the coating fraction at 10 atm if the temperature increased? - What would happen to the volume of the monolayer if the temperature increased? - Using the Langmuir isotherm, estimate the value of the adsorption equilibrium constant. Tip: use the overlay fraction at 10 atm (already calculated in item b) and calculate the value of K. ANSWER: 0.45